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3 years ago

9

Identify the slope of the line shown in the graph below:

1 answer:

MrRissso [65]3 years ago

4 0

I believe the slope of any vertical line is "undefined" because slope= rise(change in y values)/ run(change in x values).

Therefore, the slope for a horizontal line is
m= 0/(x2-x1).

However, for a vertical line the x-values are the values that are not changing. So, m= (y2-y1)/0. It is not possible to divide anything by zero. So, the slope of a vertical line is reported as m= undefined.

Any questions?

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If a and b are the roots of the quadratic equation 2r + 6x -7 = 0, form the equation with the following causes.

Pepsi [2]

Answer:

Step-by-step explanation:

Assuming the given equation is actually $2x^2+6x-7=0$ .

Then $\alpha +\beta=-\frac{6}{2} =-3,and,\alpha \beta=-\frac{7}{2}$

The sum of roots of the new equation is $\frac{1}{2\alpha+1} +\frac{1}{2\beta +1} =\frac{2(\alpha+\beta+1)}{4\alpha \beta+2(\alpha +\beta)+1}$

$\implies \frac{1}{2\alpha+1} +\frac{1}{2\beta +1} =\frac{2(-3+1)}{4*-3.5+2(-3)+1} =\frac{4}{19}$

The product of the roots of the new equation is $\frac{1}{2\alpha +1}*\frac{1}{2\beta+1}=\frac{1}{4\alpha \beta+2(\alpha+\beta)+1}$

$\implies \frac{1}{2\alpha +1}*\frac{1}{2\beta+1}=\frac{1}{4*-3.5+2(-3)+1} =-\frac{1}{19}$

The new equation is given by:

$x^2-(sum\:of\:roots)x+product\:of\:roots=0$

$x^2-\frac{4}{19} x-\frac{1}{19} =0$

$19x^2-x-1=0$

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4 years ago

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