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raketka [301]
3 years ago
5

What is the equation of this graphed line?

Mathematics
1 answer:
pantera1 [17]3 years ago
4 0

Answer:

y = - \frac{1}{3} x - 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 3) and (x₂, y₂ ) = (6, - 7)

m = \frac{-7+3}{6+6} = \frac{-4}{12} = - \frac{1}{3}

Note the line crosses the y- axis at (0, - 5) ⇒ c = - 5

y = - \frac{1}{3} x - 5 ← equation of line

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Step-by-step explanation:

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2 years ago
the total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib. if the weight of the bag of sugar is 1.4 Ib, what is the we
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0.4 lbs each.

<h3>Further explanation</h3>

<u>Given: </u>

  • The total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib.
  • The weight of the bag of sugar is 1.4 Ib

<u>Question: </u>

What is the weight of each piece of butter?

<u>The Process: </u>

The two steps for obtaining the weight of each piece of butter are as follows:

<u>Step-1:</u> the total amount of butter is the total bag of butter and sugar subtracted by the weight of the bag of sugar.

\boxed{ \ 3.8 \ lbs - 1.4 \ lbs = 2.4 \ lbs \ }

<u>Step-2:</u> the total amount of butter divided by the number of pieces of butter is the the weight of each piece of butter.

\boxed{ \ 2.4 \ lbs \div 6 \ pieces = \boxed{ \ 0.4 \ lbs/piece \ } \ }

Let's also consider the following quick steps.

<u>Quick steps: </u>

\boxed{ \ \frac{(3.8 - 1.4) \ lbs}{6 \ pieces} = \boxed{ \ 0.4 \ lbs/piece \ } \ }

Therefore, the weight of each piece of butter is 0.4 lbs.

<h3>Learn more </h3>
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Keyword: the total weight, 6 pieces of butter, a bag of sugar is 3.8 Ib, if the weight of the bag of sugar is 1.4 Ib, each piece, subtracted, divide

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