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dem82 [27]
3 years ago
6

Find the results combining these functions.

Mathematics
1 answer:
vodomira [7]3 years ago
4 0
Given f(x) = x^2 + 6x + 9, g(x) = x^2 - 9:

(f+g)(x) = (x^2 + 6x+9)+(x^2-9) =2x^2+6x=2x(x+3), which is the second expression

(f-g)(x) = (x^2 + 6x+9)-(x^2-9) =6x+18=6(x+3), which is the first second expression

(fxg)(x) = (x^2+6x+9)(x^2-9) = (x^4-9x^2)+(6x^3-54x)+(9x^2-81)=x^4+6x^3-54x-81, which is the fourth expression

(f/g)(x) = (x^2+6x+9)/(x^2-9) = \frac{(x+3)^2}{(x+3)(x-3)} = \frac{x+3}{x-3}, which is the third expression
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Step-by-step explanation:

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3 years ago
How do you add 323+412 in base 5
Alenkasestr [34]

Answer:

Addition of 323+412 = 1240 at base 5

Step-by-step explanation:

We have to add 323+412 on base 5

As we have to use base 5 for addition so we can use only numbers 0,1,2,3.4 and 5 as we use 0,1,2,3,4,5,6,7,8,9,10 in decimal when base is 10

Means in addition of sum is greater than 5 then we have to take carry as in base 10 we take carry if the sum is greater than 10

So sum 323+412 = 1240

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3 years ago
Please help with this question, thanks!
sweet [91]

The first box would be 2 and the second box would be 11.

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3 years ago
I thought i knew this but i don't. Can someone help?
Goshia [24]
Im pretty sure the answer is B

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3 years ago
(52)-3.54/5-4 what is the answer to this question
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Step-by-step explanation:

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