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kvasek [131]
3 years ago
10

probability that cars have been assembled in a particular plant as follows: P(plant1)=20% , P(plant 2)=24% , P(plant 3.25% , P(p

lant 4)=31% Total number of cars manufactured by all plants: 1.2 million/year Number of cars of no warranty claims manufactured by plant1: 223200/year Compute the warranty claim rate of the cars assembled in plant 1
Mathematics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

16800/year

Step-by-step explanation:

Plant 1= 20%

Plant 2 = 24%

Plant 3 = 25%

Plant 4 = 31%

Total cars produced 100% = 1,200,000

Number of cars produced in plant 1 =

20% of 1,200,000 = 0.2 x 1,200,000 = 240,000 cars

Number of cars produced in plant 2 =

24% of 1,200,000 = 0.24 x 1,200,000 = 288,000 cars

Number of cars produced in plant 3 =

25% of 1,200,000 = 0.25 x 1,200,000 = 300,000 cars

Number of cars produced in plant 4 =

31% of 1,200,000 = 0.31 x 1,200,000 = 372,000 cars

Number of cars with no warranty claim in plant 1/year 223200

Number of cars with warranty claims in plant 1 + number of cars with no warranty claim in plant 1  = total number of cars produced in plant 1

X + 223200 = 240000  

X = 240000 - 223200

X = 16800/year

number of cars with warranty claim in plant 1/ year is 16800

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