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Tpy6a [65]
3 years ago
6

Calculate the tax amount they pay in a form of tax (tax =R14 850)​

Mathematics
1 answer:
seraphim [82]3 years ago
4 0

Answer:

246373737

Step-by-step explanation:

good luck

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jeff wants to buy a phone card for long distance calls. he can buy a 200-minute card for $10.00 or a 300-minute card for $12.00.
Alenkasestr [34]
200 min / $10.00 = 20 minutes / dollar 

<span>300 min / $12.00 = 25 minutes / dollar </span>

<span>The cost of the 300 minute card is cheaper per minute and a better value. </span>

<span>If you don't expect to use more than 200 minutes then save your money and buy the smaller card.</span>
3 0
3 years ago
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Marcos pool is leaking 1/2 gallon per hour. he finds a 5 gallon bucket to catch the water. How many hours will it take to fill t
Rom4ik [11]
It would take ten hours.
7 0
3 years ago
Shaq painted 600 portraits in 8 hours at that rate how many portraits would he paint in 4 minutes?
Deffense [45]

Answer: In 4 minutes he will make 5 portraits

Step-by-step explanation:

\large \boldsymbol{} 600p-8h=480 min  \\\\ x \ p-4  min   \\\\ x=\dfrac{600\cdot 4}{480} =\dfrac{2400}{480} =5  \ portraits \\\\ \rm Answer : 5

3 0
2 years ago
A truck can be rented from Company A for ​$40 a day plus ​$0.40 per mile. Company B charges ​$20 a day plus ​$0.50 per mile to r
torisob [31]

The number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles

The Company A rented the truck for $40 a day plus $0.40 per miles

The expression will be

40+0.40x

Where x  is the number of miles

The company B rented the truck for $20 a day plus $0.50 per miles

20+0.50x

To find the number of miles in a day at which the rental costs for Company A and Company B are the same, the linear equation will be

40+0.40x = 20+0.50x

40-20 = 0.50x-0.40x

0.1x = 20

x = 200 miles

Hence, the number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles

Learn more about linear equation here

brainly.com/question/13738061

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6 0
10 months ago
How do i solve this question
frozen [14]
\bf \begin{cases}&#10;h(x)=(f\circ g)(x)\\&#10;h(x)=\sqrt{x+5}\\&#10;f(x)=\sqrt{x+2}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;(f\circ g)(x)\implies f[\ g(x)\ ]\implies f[\ g(x)\ ]=\sqrt{g(x)+2}\qquad thus&#10;\\\\\\&#10;\sqrt{g(x)+2}=(f\circ g)(x)=h(x)=\sqrt{x+5}\qquad therefore&#10;\\\\\\&#10;\sqrt{g(x)+2}=\sqrt{x+5}\impliedby \textit{squaring both sides}\\\\\\&#10;g(x)+2=x+5\implies g(x)=x+5-2\implies \boxed{g(x)=x+3}
8 0
3 years ago
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