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Damm [24]
2 years ago
8

In the diagram, the measure of angle 9 is 85°.

Mathematics
1 answer:
Simora [160]2 years ago
6 0

Answer:

Angle 5 (corresponding angle)

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post a clear picture plizz we will help it is blank

Step-by-step explanation:

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3 years ago
What is the value of the expression 8-(2to the 3rd Power+48)divided by 8
dalvyx [7]
8-(8+48) = -48 then divide that by 8 and you get -6 as your result
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Calculate the total cost of an item bought at a negotated price of $13,290 with 5.5 percent sales tax and a $125 registration fe
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C=13290+13290(.055)+125=$14145.95<span>
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7 0
2 years ago
A Class 4 truck weighs between 14,000 and 16,000 pounds.
Nady [450]

Answer:

Class 4: This class of truck has a GVWR of 14,001–16,000 pounds or 6,351–7,257 kilograms. Class 5: This class of truck has a GVWR of 16,001–19,500 pounds or 7,258–8,845 kilograms.

Step-by-step explanation:

6 0
2 years ago
Write an equation that goes through (8,1) and is perpendicular to 2y + 4x =12
Serggg [28]

Answer:

2y -x + 6 = 0

Step-by-step explanation:

Here a equation and a point is given to us and we are interested in finding a equation which is perpendicular to the given equation and passes through the given point .

The given equation is ,

\sf \longrightarrow 2y + 4x = 12 \\

\sf \longrightarrow 4x + 2y = 12

Firstly convert this into slope intercept form , to find out the slope of the line.

\sf \longrightarrow 2y = -4x +12\\

\sf \longrightarrow y =\dfrac{-4x+12}{2}\\

\sf \longrightarrow y =\dfrac{-4x}{2}+\dfrac{12}{2}\\

\sf \longrightarrow \red{ y = -2x + 6 }

Now on comparing it to slope intercept form which is y = mx + c , we have ,

  • m = -2

And as we know that the product of slopes of two perpendicular lines is -1 . So the slope of the perpendicular line will be negative reciprocal of the slope of the given line. Therefore ,

\sf \longrightarrow m_{\perp}=\dfrac{-1}{-2}=\red{\dfrac{1}{2}}

Now we may use the point slope form of the line to find out the equation of the line using the given point . The point slope form is,

\sf \longrightarrow y - y_1 = m(x - x_1)

Now on substituting the respective values we have,

\sf \longrightarrow y - 1 = \dfrac{1}{2}(x-8)\\

\sf \longrightarrow 2(y-1 )= x -8 \\

\sf \longrightarrow 2y -2=x-8\\

\sf \longrightarrow \underline{\boxed{\bf 2y - x + 6=0}}

5 0
2 years ago
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