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Arada [10]
4 years ago
13

2x+11=21 solve for the indicated variable

Mathematics
1 answer:
Drupady [299]4 years ago
3 0

Here is the equation:

2x+11=21

Leave the variable alone by subtracting 2 from both sides:

2x+11 = 21 \\ 2x - 11 = 21-11

The new equation becomes:

2x=10

Leave the variable alone(again) by dividing both sides by 2:

2x \div 2 = 10 \div 2

Simplify and it becomes:

x = 5

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1/6

Step-by-step explanation:

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Help me solve 3 and 4 please
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What is the product of 2 2/3 and 2/5
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Whats the value of 1¹²​
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Step-by-step explanation:

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6 0
3 years ago
What is the solution of StartRoot x squared + 49 EndRoot = x + 5?
Natasha2012 [34]

x=\frac{12}{5} or x= twelve-fifths

Option A is correct.

Step-by-step explanation:

We need to find the solution of:

\sqrt{x^2+49}=x+5

Solving:

Taking square on both sides:

(\sqrt{x^2+49})^2=(x+5)^2\\x^2+49=x^2+2(x)(5)+25\\Simplifying:\\x^2+49-x^2-10x-25=0\\-10x+24=0\\-10x=-24\\x=\frac{-24}{-10}\\ x=\frac{24}{10}\\x=\frac{12}{5}

Verifying the solution by putting x = 12/5 in the given equation, we get true result.

So, x=\frac{12}{5} or x= twelve-fifths

Option A is correct.

Keywords: Solving Square root Equations

Learn more about Solving Square root Equations at:

  • brainly.com/question/4034547
  • brainly.com/question/1716201
  • brainly.com/question/10666510

#learnwithBrainly

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