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4 years ago

Help me solve 3 and 4 please

Mathematics

1 answer:

Leni [432]4 years ago

4 0

Answer: Number 3 : 20/21

Number 4: 1/6

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11-8n=1-3n whats answer

musickatia [10]

Answer:

n=2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

11−8n=1−3n

11+−8n=1+−3n

−8n+11=−3n+1

Step 2: Add 3n to both sides.

−8n+11+3n=−3n+1+3n

−5n+11=1

Step 3: Subtract 11 from both sides.

−5n+11−11=1−11

−5n=−10

Step 4: Divide both sides by -5.

−5n

−5

−10

−5

n=2

6 0

4 years ago

What is the answer to the question? 2x^2=10x

Lina20 [59]

Answer:

The correct answer is 0 or 5

Step-by-step explanation:

In order to solve this, solve for 0.

2x^2 = 10x

2x^2 - 10x = 0

Now factor the polynomial.

x(2x - 10) = 0

Now set each piece individually equal to 0.

x = 0

2x - 10 = 0

2x = 10

x = 5

7 0

3 years ago

Read 2 more answers

50 points.

Sphinxa [80]

Answer:

Step-by-step explanation:

Using the rules of exponents

$(a^m)^{n}$ = $a^{mn}$

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$

Given

$(\frac{1}{x^{(a-b)}) } ^{a+b}$ × $(\frac{1}{x^{b+a}) } ^{b-a}$

= $\frac{1}{x^{(a-b)(a+b)} }$ × $\frac{1}{x^{(b+a)(b-a)} }$

= $\frac{1}{x^{(a^2-b^2)} }$ × $\frac{1}{x^{(b^2-a^2)} }$

= $\frac{1}{x^{(a^2-b^2+b^2-a^2)} }$

= $\frac{1}{x^{0} }$

= $\frac{1}{1}$

= 1

5 0

3 years ago

Read 2 more answers

Plsss anyone help meee plsss

Volgvan

Answer:

yes what do you want help with

8 0

3 years ago

Pls help I don't understand the question

barxatty [35]

Answer:

Answers B I think.

Step-by-step explanation:

I assume t is time so the variable would equal the time it hit the floor

3 0

3 years ago