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3 years ago

A line has a zero slope and passes through the point (-5,4). What is the equation of the line?

Mathematics

1 answer:

zhenek [66]3 years ago

5 0

Answer:

y=4

Step-by-step explanation:The answer is y=4 because the line has no slope so it will not increase or decrease at a constant rate. If we were to plug it in it would be y=0/0+4. this basically means that the y-axis is equivalent to 0/0 (no slope) plus 4, we can then cancel out 0 since it is nothing simplifying the equation to y=4.

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Trapezoid p is the image of trapezoid P after a translation. Y 7+ . р на дъл от - 1 -7-6-5-4-3-2-1 -2+ 11 2 3 4 5 6 7 1 PY 1 - -

zavuch27 [327]

Answer:

C. 8 units right and 5 units down

Step-by-step explanation:

since it's only a translation, take one point as an example. lets say the bottom right point on trapezoid P is point A, and the translated point on P' is A'. the coordinates of A are (-3,2) while the coordinates of A' are (5,-3). (-3+x,2+y)=(5,-3). -3+x=5, x=8; 2+y=-3, y=-5

3 0

2 years ago

20 pounds to 16 pounds is what present

ExtremeBDS [4]

Answer:

Decreased by 20%.

16 lbs is 80% of 20 lbs.

Step-by-step explanation:

$\frac{y}{100} :\frac{16}{20}$

y × 20 = 16 × 100

20y = 1600

20y ÷ 20 = 1600 ÷ 20

y = 80

100% - 80% = 20%

6 0

3 years ago

Read 2 more answers

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

2 years ago

What is the proof for this?

Butoxors [25]

Knowing nexnjhdjhdhfgnu. Hngj

5 0

3 years ago

X + 2y = 10

Crazy boy [7]

Answer:

(-12,11)

Step-by-step explanation:

x + 2y = 10

3x + 4y = 8

(-2)x + (-2)2y = (-2)10

3x + 4y = 8

-2x - 4y = -20

3x + 4y = 8

Add to eliminate:

x = -12

Substitute x to solve y:

x + 2y = 10

(-12) + 2y = 10

-12 + 2y = 10

2y = 10 + 12

2y = 22

y = 22 ÷ 2

y = 11

Check:

x + 2y = 10

(-12) + 2(11) = 10

-12 + 22 = 10

10 = 10

8 0

3 years ago

Read 2 more answers