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Andreas93 [3]
3 years ago
12

X + 3y = 18 -X - 4y = -25

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
4 0

Answer:

x = -3

y= 7

Step-by-step explanation:

x + 3y=18 ----(1)

-x - 4y=-25 -----(2)

from equation (1)

x = 18 - 3y ---(3)

putting equation (3) into equation (2)

-(18 - 3y) - 4y = -25

18 + 3y -4y = -25

3y - 4y = -25 - 18

-y = -7

y = 7 ✓

Putting y=7 into equation (1)

x + 3(7) = 18

x + 21 = 18

x = 18 - 21

x = -3 ✓

SVEN [57.7K]3 years ago
3 0
-y=-7
Y=7
-x-4(-7)=-25
-x+28=-25
-x=3
X=-3
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What is another way to write 0.7?
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7/10. Because 0.7 equals 70% . As a fraction it would be 70/100. Simplify, and you get 7/10. 
8 0
3 years ago
-36.12 divided by -5 3/5
Nataliya [291]
<h3 /><h3>- 36.12 \div  - 5 \frac{3}{5}  \\  - 36.12 \div  -  \frac{28}{5}  \\  = 6.45</h3>

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

5 0
2 years ago
What is the distance rounded to the nearest tenth between the points (2 -2) and (6 3)
kotegsom [21]

Answer:

The distance between the points is approximately 6.4

Step-by-step explanation:

The given coordinates of the points are;

(2, -2), and (6, 3)

The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Substituting the known 'x', and 'y', values for the coordinates of the points, we have;

l_{(2, \, -2), \ (6, \, 3) } = \sqrt{\left (3-(-2)  \right )^{2}+\left (6-2  \right )^{2}} = \sqrt{5^2 + 4^2} = \sqrt{41}

Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.

4 0
3 years ago
Please solve this sheet.
lyudmila [28]
Hello,

A: roots: -1,-3
a point (-2,1)
Vertex=((-2,1)

y=k*(x+1)(x+3) using roots
but k*(-2+1)(-2+3)=1==>k*(-1)*1=1==>k=-1

eq: y=-(x+1)(x+3)
==>y=-(x²+3x+x+3)
==>y=-x²-4x-3
y=k(x+2)²+1 if x=-1,y=0 ==>k*1+1=0==>k=-1
==>y=-(x+2)²+1

Answer :A--> R,K

B)
y=k(x+4)²-2 and k=-1/2
y=-1/2(x+4)²-2
y=-1/2x²-4x-10

answer B--> I,≈W if it is written -1/2*x²  (square has been forgotten)

C:
y=2x²-16x+30
y=2(x-4)²-2
answer : C-->S,J

D:
y=-(x+3)(x+1)
y=-x²-4x-3
=-(x+2)²+1
answer D--> V,L

E:
Here there is a problem: or the graph is wrong, or 2 equations are missing!

y=1(x+1)(x-3) using roots
y=x²-2x-3 ≈ T si it were -2x and not +2x.

y=(x-1)²-4 ≈H is it were -1 in place of +1 [H:y=(x+1)²-4]




6 0
3 years ago
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