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gayaneshka [121]
2 years ago
12

Danny's truck has a fuel tank with a capacity of 20 gallons of gas. The truck averages 17 miles per gallon of gas. The function

M(g) = 17g represents the number of miles that Danny's truck travels on g gallons of gas. What domain and range are reasonable for the function?
A. D: 0 ≤ g ≤ 340
R: 0 ≤ M(g) ≤ 20
B. D: 0 ≤ g ≤ 20
R: 17 ≤ M(g) ≤ 340
C. D: 17 ≤ g ≤ 20
R: 20 ≤ M(g) ≤ 340
D. D: 0 ≤ g ≤ 20
R: 0 ≤ M(g) ≤ 340
Mathematics
1 answer:
Fittoniya [83]2 years ago
5 0

For this case we have the following function:

M (g) = 17g

Where,

g: number of gallons of gas

M (g): number of miles that Danny's truck travels

We know that the maximum capacity is 20 gallons of gas.

Therefore, the maximum distance the truck can travel is given by:

M (20) = 17 (20)

M (20) = 340

Thus, the domain of the function is:

0 \leq g \leq 20

The range of the function is:

0 \leq M(g) \leq 340

Answer:

A domain and range that are reasonable for the function are:

D. D: 0 ≤ g ≤ 20

R: 0 ≤ M (g) ≤ 340

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\bf \begin{array}{lccclll}
&\stackrel{lbs}{syrup}&\stackrel{concentration~\%}{syrup}&\stackrel{concentration}{amount}\\
&------&------&------\\
\textit{25\% syrup}&10&0.25&2.5\\
\textit{pur water}&x&0.00&0.00x\\
------&------&------&------\\
\textit{10\% mixture}&y&0.10&0.10y
\end{array}
\\\\\\
\begin{cases}
10+x=\boxed{y}\\
2.5+0.00x=0.10y\\
----------\\
2.5 = 0.10\left( \boxed{10+x} \right)
\end{cases}
\\\\\\
2.5=1 + 0.10x\implies 1.5=0.10x
\\\\\\
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