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snow_lady [41]
3 years ago
14

(-4,5) and (4,0) find the distance between each pair of points

Mathematics
1 answer:
aleksklad [387]3 years ago
6 0

Answer:

9.4339 units

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where

(x_1,y_1) = (-4,5)

(x_2,y_2) = (4,0)

Replacing these values in the distance formula

D =\sqrt{(-4-4))^2+(5-0)^2}

D =\sqrt{(-8)^2+(5)^2}

D =\sqrt{64+25}

D =\sqrt{89}

D= 9.4339

Hence the distance is 9.4339 units

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The equation of a quadratic is =2^2+3−2and after you factorizing 2^2+3−2=0you got x = -2 and x = 1/2 and the curve crosses the y
Lelechka [254]

Given the next quadratic function:

y=2x^2+3x-2

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

x_V=\frac{-b}{2a}

where <em>a</em> and <em>b</em> are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

\begin{gathered} x_V=\frac{-3}{2\cdot2} \\ x_V=-\frac{3}{4}=-0.75 \end{gathered}

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

\begin{gathered} y_V=2x^2_V+3x_V-2 \\ y_V=2\cdot(-\frac{3}{4})^2+3\cdot(-\frac{3}{4})-2 \\ y_V=2\cdot\frac{9}{16}+3\cdot(-\frac{3}{4})-2 \\ y_V=\frac{9}{8}-\frac{9}{4}-2 \\ y_V=-\frac{25}{8}=-3.125 \end{gathered}

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:

6 0
1 year ago
On a coordinate plane, a line goes through (0, negative 3) and (3, negative 2). A point is at (negative 4, 2).
bulgar [2K]

Answer:

Correct option: first one -> y = (1/3)x + (10/3)

Step-by-step explanation:

The linear function that represents a line is:

y = ax + b

Where a is the slope and b is the y-intercept.

First we need to find the slope of the line that goes through (0, -3) and (3, -2).

Using both points, we can find the equation of the line:

x = 0 -> y = -3

-3 = a*0 + b

b = -3

x = 3 -> y = -2

-2 = 3a - 3

3a = 1

a = 1/3

The parallel line needs to have the same slope as the line, so we can model the parallel line with the following equation:

y = (1/3)x + b

The parallel line goes through the point (-4, 2), so we have:

x = -4 -> y = 2

2 = (1/3)*(-4) + b

b = 2 + (4/3)

b = 10/3

So the equation of the parallel line is:

y = (1/3)x + (10/3)

Correct option: first one

5 0
3 years ago
What are the factors of 13m-2n
Lelechka [254]
<span>the first term 13m has TWO factors 13 and m
the second term 2n has TWO factors 2 and n</span>
3 0
3 years ago
Read 2 more answers
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