Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π that is closest to the origin O=(0,0,0).
Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e.
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane Π , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane Π
Answer: P(-2/13, -3/26, 1/26) is the point on Π closest to the origin.
He has 4 plums left :) (and in case your wondering he still has 6 apples)
That is simple all you have to do is multiply the number of white cars by 9 and you will get your answer. 40*9=360
Answer:
1/6
Step-by-step explanation:
there are 6 faces on a dice so there's a 1 in 6 chance that you would roll a 3 on your second go there is still only a 1 out of 6 chance of getting a 5 because there is still 6 numbers you could roll on.
hope this helped
