A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer: income
Step-by-step explanation:
If the distance around the earth means circumference, it is, 24,887.64.(not rounded.) C=pi D (pi=3.14 + d=diameter)
(4y-3)(2y²+3y-5)
First , let's start with "4y"
4y*2y² = 8y³
4y*3y = 12y²
4y*-5 = -20y
Next, let's multiply by "-3"
-3*2y² = -6y²
-3*3y = -9y
-3*-5 = 15
Now, let's combine all of our values.
8y³+12y²-6y²-20y-9y+15 = 8y³+6y²-29y+15
