The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
Answer:
2x -3 =2x + 3
Step-by-step explanation:
Addition is commutative so as subtraction so 2x-3=2x+3
Answer:
125.8983
Step-by-step explanation:
Use the formula for volume of a cone: v= (1/3)(3.14)(radius squared)(height) so v = (1/3)(3.14)(20.25)(6) = 125.8983
The multiplier to get from 6 * ... to 15 is 15/6.
If 6 * 15/6 = 15, then 20 * 15/6 = 50, answer B.
C. 5 units is the answer and I am typing to make in 20 characters long.