Try this, I think its correct
Answer:
can be written in power notation as 
Step-by-step explanation:
The given expression

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:
Let

= ![[13\times13][(a\times (-a)\times a\times (-a)]](https://tex.z-dn.net/?f=%5B13%5Ctimes13%5D%5B%28a%5Ctimes%20%28-a%29%5Ctimes%20a%5Ctimes%20%28-a%29%5D)
As
,
,
So,
![=[13^{2}][a^2\times (-a)^2]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E2%5Ctimes%20%28-a%29%5E2%5D)
As

So,
![=[13^{2}][a^2\times a^2]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E2%5Ctimes%20a%5E2%5D)
As ∵
![=[13^{2}][a^{2+2}]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E%7B2%2B2%7D%5D)
As ∵


Therefore,
can be written in power notation as 
<em>Keywords: power notation</em>
<em>Learn more about power notation from brainly.com/question/2147364</em>
<em>#learnwithBrainly</em>
Answer:
Ok, we know that we can write a horizontal translation as:
y' = f(x - A)
where if A is positive, this moves the graph of f(x) A units to the right.
Why is this?
Ok, let's compare:
y = f(x)
and
y' = f(x - A)
in y, when x = 0 we have f(0).
While to have this same point in y', we need to evaluate in x = A.
f(A - A) = f(0).
Then the value f(0) is now at x = A, this means that the point moved A units to the right.
And you can do this for all the values, so you will find that the entire graph of f(x) has ben moved A units to the right.
Answer:
2π
Step-by-step explanation:
Area = πr^2
= π2^2
= 4π
4π is the area of the whole circle, so divide it in half to get the semicircle.
<u>= 2π</u>
Answer:
21
Step-by-step explanation:
30x2=60
60x.35=21
Mark me brainliest i really need it