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tia_tia [17]
3 years ago
7

When researchers cool a gas, which of the following has occurred? Select all that apply.

Chemistry
2 answers:
Alenkasestr [34]3 years ago
8 0
I think that there would be two correct answers from the choices listed above. When researchers cool a gas, velocity and spacing of particles is reduced and the v<span>olume of substance decreases relative to temperature decrease. Hope this answers the question. Have a nice day.</span>
Ne4ueva [31]3 years ago
5 0

Answer is: Velocity and spacing of particles is reduced and Volume of substance decreases relative to temperature decrease.

Charles' Law (The Temperature-Volume Law) - the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:

V₁/T₁ = V₂/T₂.

When temperature goes down, the volume also goes down.

Velocity is equivalent to a specification of its speed and direction of motion, it is a physical vector quantity. Less enegry (lower temperature), lower the velocity.

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What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.0×1015Hz?
Anvisha [2.4K]
In order to emit electrons, the cesium will have to absorb photons. Each photon will knock out one electron by transferring its energy to the electron. Therefore, by the principle of energy conservation, the energy of the removed electron will be equal to the energy of the incident photon. That energy is calculated using Planck's equation:

E = hf

E = 6.63 x 10⁻³⁴ * 1 x 10¹⁵
E =  6.63 x 10⁻¹⁹ Joules

The electron will have 6.63 x 10⁻¹⁹ Joules of kinetic energy
3 0
3 years ago
Submit your answer for the remaining reagent in Tutorial Assignment #1 Question 9 here, including units. Note: Use e for scienti
djverab [1.8K]
<h3>Answer:</h3>

The mass of excessive water (H₂O) is 40.815 kg

<h3>Explanation:</h3>

The Equation for the reaction is;

Li₂O(s) + H₂O(l) → 2LiOH(s)

From the question;

Mass of water removed is 80.0 kg

Mass of available Li₂O is 65.0 kg

We are required to calculate the mass of excessive reagent.

<h3>Step 1: Calculating the number of moles of water to be removed</h3>

Moles = Mass ÷ Molar mass

Molar mass of water = 18.02 g/mol

Mass of water = 80 kg (but 1000 g = 1kg)

                        = 80,000 g

Therefore;

Moles of water = \frac{80,000g}{18.02 g/mol}

                = 4.44 × 10³ moles

<h3>Step 2: Moles of Li₂O available </h3>

Moles = mass ÷ molar mass

Mass of Li₂O  available = 65.0 kg or 65,000 g

Molar mass Li₂O  = 29.88 g/mol

Moles of Li₂O  = 65,000 g ÷ 29.88 g/mol

          = 2.175 × 10³ moles Li₂O

<h3>Step 3: Mass of excess reagent </h3>

From the equation; Li₂O(s) + H₂O(l) → 2LiOH(s)

1 mole of Li₂O reacts with 1 mole of water to form two moles of LiOH

The ratio of Li₂O to H₂O is 1:1

  • Thus, 2.175 × 10³ moles of Li₂O will react with 2.175 × 10³ moles of water.
  • However, the number of moles of water to be removed is 4.44 × 10³ moles  but only 2.175 × 10³ moles will react with the available Li₂O.
  • This means, Li₂O  is the limiting reactant while water is the excessive reagent.

Therefore:

Moles of excessive water =  4.44 × 10³ moles  - 2.175 × 10³ moles

                                           = 2.265 × 10³ moles

Mass of excessive water = 2.265 × 10³ moles × 18.02 g/mol

                                          = 4.0815 × 10⁴ g or

                                          = 40.815 kg

Thus, the mass of excessive water is 40.815 kg

7 0
3 years ago
Which type of wave has a disturbance that moves parallel to direction the energy in the waves travels?
Len [333]
The correct answer is B.LONGITUDINAL WAVES.
6 0
2 years ago
What is the best description for a solution with a hydroxide-ion concentration equal to 1 x 10-4 m?
djverab [1.8K]

Answer:

This is a basic solution

Explanation:

To be able to provide a succint description of this solution, from the given parameters we can deduce the pH of the solution.

Given parameters:

Concentration of OH⁻ = 1 x 10⁻⁴M

Solution

          We knonw that pOH = -log₁₀[OH⁻]

                   pOH = -log₁₀ 0.0001 = - (-4) = 4

For an aqeous solution:

                  pH + pOH = 14

                  pH = 14 - 4 = 10

The pH of the solution has been derieved to be 10

This is a basic solution

7 0
3 years ago
What precautions should be observed when an aqueous sodium carbonate solution is used to extract an organic solution containing
Vladimir [108]
<span>The biggest precaution that should be followed is to not wall the separatory funnel off too tightly. When the sodium carbonate solution is used, the acid will react with it to create carbon dioxide. This can build up in the funnel, leading to an increase in pressure that could cause a rupture if enough is created.</span>
3 0
3 years ago
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