Answer:
2.93g
Explanation:first, let us calculate the number of mole of NaCl present in the solution. This is illustrated below:
Molarity = 0.5M
Volume = 100cm^3 = 100/1000 = 0.1L
Mole =?
Molarity = mole /Volume
Mole = Molarity x Volume
Mole of NaCl = 0.5 x 0.1 = 0.05mole
Now we can obtain the mass of NaCl as follows:
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
Mole of NaCl = 0.05mol
Mass of NaCl =?
Mass = number of mole x molar Mass
Mass of NaCl = 0.05 x 58.5
Mass of NaCl = 2.93g
Answer:
The mass of 
in the container is 2.074 gram
Explanation:
Given:
Volume of 
lit
Equilibrium constant 
The reaction in which is produced
⇄ 
Here equal moles of and 
is formed.
From the formula of equilibrium constant,
M
Above value shows,
So in 2 L no. moles of = 
moles.
So mass of 0.122 mole of is = 
g
Therefore, the mass of in the container is 2.074 gram
Answer:
it is a base because they accept H+ ions
Explanation:
