The question is incomplete. Complete question is attached below:
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Correct Answer:
Option A i.e FlammabilityReason:
Hydrochloric acid is a
strong acid. It has a high value of dissociation constant. Following equilibrium is established with HCl is dissolved in water
HCl + H2O ↔ Cl- + H3O+
Above, reaction is highly exothermic in nature. So care must be taken while preparing HCl solution of desired concentration.
HCl must be added in beaker containing water. Reversed, i.e. adding water in HCl, must never be done. This is because when acid is poured into water, it flows down the flask and mixes much efficiently and no boiling occurs. On other hand, <span> when water is added to acid, the very first drop of water will react with acid. The heat generated during this event might be high enough to boil the water instantly, which could spray acid out of the container.
The physical contact with concentration HCl will result in skin burn. As well, inhaling</span><span> HCl vapors can cause burns to body tissues, lung damage and even death in extreme cases. Also, since HCl is a strong acid, it would undergoes reaction almost spontaneously, which would inturn favour substitution reaction. However,
HCl is not a flammable gas. Hence, it is of no concern while performing substitution reaction. </span>
<span>(2.25moles)*(6.022x10^23) </span>
Answer:
1) The concentration of HCl = 0.1 M.
2) The table that can be used to organize the information correctly is C.
Explanation:
<u><em>1) The concentration of HCl:</em></u>
- We know that the no. of millimoles of the acid is equal to the no. of millimoles of the base at the neutralization point.
which means that: <em>(MV)HCl = (MV)NaOH,</em>
M of HCl = ??? M, V of HCl = 25.0 mL.
M of NaOH = 0.2 M, V of NaOH = 12.5 mL.
∴ M of HCl = (MV)NaOH/V of HCl = (0.2 M)(12.5 mL)/(25.0 mL) = 0.1 M.
<em>2) The table that can be used to organize the information correctly is C</em>
<em></em>
<em>Table A and B are the same and reported volume of HCl and NaOH is wrong.</em>
<em>Table C is right, contain the correct volumes and concentration of NaOH and missed the concentration of HCl which is 0.1 M.</em>
<em>Table D reported the volume and the concentration of HCl wrongly and also the concentration of NaOH. The data reported of HCl and NaOH is reversed.</em>
This reaction does not exist since all of the reactants and products are aqueous.