Explanation:
1 literThe total of water is equal to 1000.0 g of water
we need to find the molality of a solution containing 10.0 g of dissolved in Na₂S0₄1000.0 g of water
1. For that find the molar mass
Na: 2 x 22.99= 45.98
S: 32.07
O: 4 x 16= 64
The total molar mass is 142.05
We have to find the number of moles, y
To find the number of moles divide 10.0g by 142.05 g/mol.
So the number of moles is 0.0704 moles.
For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.
The molarity would end up being 0.0704 M
The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is 0.0704 Mliter
Answer:
26.74g
Explanation:
The equation of the reaction is;
SIO₂ + 3C --> SiC +2CO
From the balanced equation, the relationship between SiC and C is;
3 mol of C produces 1 mol of SiC
Converting mol to mass using; Mass = moles * Molar mass
Mass of SiC = 1 mol * 40.11 g/mol = 40.11g
This means;
3 mol of C produces 40.11g of SiC
2 mol of C produces xg of SiC
3 = 40.11
2 = x
x = 2 * 40.11 / 3 = 26.74g
False
The stirring allows fresh solvent molecules to continually be in contact with the solute. If it is not stirred, then the water right at the surface of the solute becomes saturated with dissolved sugar molecules, meaning that it is more difficult for additional solute to dissolve.
