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Gwar [14]
3 years ago
11

Atmospheric pressure at sea level is equal to a column of 760 mm Hg. Oxygen makes up 21 percent of the atmosphere by volume. The

partial pressure of oxygen (PO2) in such conditions is _____. Atmospheric pressure at sea level is equal to a column of 760 mm Hg. Oxygen makes up 21 percent of the atmosphere by volume. The partial pressure of oxygen (PO2) in such conditions is _____. 21/760 16 mm Hg 760/21 120/75 160 mm Hg SubmitR
Chemistry
1 answer:
Neporo4naja [7]3 years ago
8 0

<u>Answer:</u> The partial pressure of oxygen is 160 mmHg

<u>Explanation:</u>

We are given:

Percent of oxygen in air = 21 %

Mole fraction of oxygen in air = \frac{21}{100}=0.21

To calculate the partial pressure of oxygen, we use the equation given by Raoult's law, which is:

p_{O_2}=p_T\times \chi_{O_2}

where,

p_{O_2} = partial pressure of oxygen = ?

p_T = total pressure of air = 760 mmHg

\chi_{O_2} = mole fraction of oxygen = 0.21

Putting values in above equation, we get:

p_{O_2}=760mmHg\times 0.21\\\\p_{O_2}=160mmHg

Hence, the partial pressure of oxygen is 160 mmHg

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For double-helix formation, DG can be measured to be 2 54 kJ mol 1 ( 2 13 kcal mol 1 ) at pH 7.0 in 1 M NaCl at 25 8C (298 K). T
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ΔS = -661.0J/mol is the entropy change for the system

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TΔS = ΔH - ΔS

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ΔS = -251 kJ/mol - ( -54 kJ/mol) / 298

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What will be the final temperature of the solution in a coffee cup calorimeter if a 50.00 mL sample of 0.250 M HCl(aq) is added
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Volume of HCl solution = V' = 50.00 mL = 0.050 L

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