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3 years ago

Which regular polygons could be used to make regular and semi-regular tessellations? Check all that apply.

Mathematics

2 answers:

fiasKO [112]3 years ago

4 0

Answer:

A,B,D,E,G

Step-by-step explanation:

Edgenuity 2020

Yanka [14]3 years ago

3 0

Answer:

A. equilateral triangle

B. square

D. regular hexagon

E. regular octagon

G. regular dodecagon

Step-by-step explanation:

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What is the result of subtracting the second equation from the first? -2x+y=0 7x+3y=2

ikadub [295]

Answer:

5x -2y = -2

Step-by-step explanation:

-2x+y=0

-7x+3y=2

Subtract the second equation from the first

-2x+y=0

7x-3y=-2

------------------

5x -2y = -2

4 0

3 years ago

Equivalent to 7^3 × 7^-2

mixas84 [53]

Answer:

Step-by-step explanation:

${7}^{ - 3} \times {7}^{ - 2}$

$= {7}^{3 - 2}$

= 7 (Ans)

3 0

3 years ago

Read 2 more answers

The time between arrivals of customers at the drive-up window of a bank follows an exponential probability distribution with a m

castortr0y [4]

Answer:

a) 50.34% probability that the arrival time between customers will be 7 minutes or less.

b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 10 minutes:

This means that $m = 10, \mu = \frac{1}{10} = 0.1$

A. What is the probability that the arrival time between customers will be 7 minutes or less?

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)$

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

$P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592$

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442$

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

3 0

3 years ago

Can some one help me with the whole paper I don’t get it

valina [46]

Answer:

I think-

1. 11

2. 0.7

3. 67.89

4. 13

Step-by-step explanation:

I'm not 100% sure tho

5 0

3 years ago

Julian study a dog walking business over his summer break. He charges $10 for every 1/3 hour he walks a dog if he increases his

Genrish500 [490]

Answer:

The amount of increase per $\frac{1}{3}$ hour by $1.

Step-by-step explanation:

Julian charges $10 for every $\frac{1}{3}$ hour he walks a dog.

He increases his fee by 10%

Now we have to find 10% of $10

Amount increased = $\frac{10}{100} .10 = 1$

So the amount increased by $1.

The amount of increase per $\frac{1}{3}$ hour by $1.

6 0

2 years ago