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timurjin [86]
2 years ago
9

The red square is the image of the blue square after a SINGLE transformation. Use two or more complete sentences to describe eac

h of the FOUR different transformations that could produce the image.

Mathematics
1 answer:
Leni [432]2 years ago
5 0

The transformations which can lead to the red square image of the blue Square are; Translation, Reflection, Rotation.

<h3>What transformations lead to the image?</h3>

  • Translation is when we slide a figure in any direction. The translation of the shape can be by moving the blue leftward or rightward and the then downward.
  • Reflection is when we flip a figure over a line. The reflection involves reflect the blue Square over the line; y = x.
  • Rotation is when we rotate a figure a certain degree around a point. The rotation is by rotating the blue Square over 180⁰.

Read more on transformations;

brainly.com/question/4289712

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You are hiking in Marin, and stop to stand on the edge of a cliff overlooking the Pacific ocean. You see a sailboat down in the
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Step-by-step explanation:

on the edge of a cliff overlooking the Pacific ocean. You see a sailboat down in the water below you. The angle of depression to the sailboat is 28◦ . A quick tells you that the cliff you’re standing on is 150ft. How far away from the boat are you, in feet, rounded to one decimal place?(30pts)

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A tank in the shape of a hemisphere has a radius of 7 feet. if the liquid that fills the tank has a density of 93 pounds per cub
professor190 [17]

The total weight of the liquid that filled the hemispheric tank to the nearest full pounds is 66775 pounds.

<h3>What is the volume of an hemisphere?</h3>

An hemisphere is half of a sphere. Therefore,

volume = 2 / 3 πr³

where,

  • r = radius

Therefore,

r = 7 feet

volume = 2 / 3 × 3.14 × 7³

volume = 2 / 3 × 3.14 × 343

volume = 2154.04 / 3

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pllllllls I need help right triangle and trigonometry special right triangles find the value of each variable​
yanalaym [24]

\huge {\mathfrak{Answer :  }}

we know,

\boxed{\cos( \theta)  =  \dfrac{base}{hypotenuse}}

so,

  • \cos(30)  =  \dfrac{24}{x}

  • \dfrac{ \sqrt{3} }{2}  =  \dfrac{24}{x}

  • x =  \dfrac{24 \times 2}{ \sqrt{3} }

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now,

\boxed{ \tan( \theta) =  \frac{perpendcular}{base}  }

  • \tan(30)  =  \dfrac{y}{24}

  • \dfrac{1}{ \sqrt{3} }  =  \dfrac{y}{24}

  • y =   \dfrac{24}{ \sqrt{3} }

  • y = 8 \sqrt{3}
6 0
3 years ago
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