Answer:
![\huge\boxed{x=-3}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7Bx%3D-3%7D)
Step-by-step explanation:
![4x+2(x-3)=3x+x-12\qquad|\text{use the distributive property}\\\\4x+(2)(x)+(2)(-3)=3x+x-12\\\\4x+2x-6=3x+x-12\qquad|\text{combine like terms}\\\\(4x+2x)-6=(3x+x)-12\\\\6x-6=4x-12\qquad|\text{add 6 to both sides}\\\\6x-6+6=4x-12+6\\\\6x=4x-6\qquad|\text{subtract}\ 4x\ \text{from both sides}\\\\6x-4x=4x-4x-6\\\\2x=-6\qquad|\text{divide both sides by 2}\\\\\dfrac{2x}{2}=\dfrac{-6}{2}\\\\x=-3](https://tex.z-dn.net/?f=4x%2B2%28x-3%29%3D3x%2Bx-12%5Cqquad%7C%5Ctext%7Buse%20the%20distributive%20property%7D%5C%5C%5C%5C4x%2B%282%29%28x%29%2B%282%29%28-3%29%3D3x%2Bx-12%5C%5C%5C%5C4x%2B2x-6%3D3x%2Bx-12%5Cqquad%7C%5Ctext%7Bcombine%20like%20terms%7D%5C%5C%5C%5C%284x%2B2x%29-6%3D%283x%2Bx%29-12%5C%5C%5C%5C6x-6%3D4x-12%5Cqquad%7C%5Ctext%7Badd%206%20to%20both%20sides%7D%5C%5C%5C%5C6x-6%2B6%3D4x-12%2B6%5C%5C%5C%5C6x%3D4x-6%5Cqquad%7C%5Ctext%7Bsubtract%7D%5C%204x%5C%20%5Ctext%7Bfrom%20both%20sides%7D%5C%5C%5C%5C6x-4x%3D4x-4x-6%5C%5C%5C%5C2x%3D-6%5Cqquad%7C%5Ctext%7Bdivide%20both%20sides%20by%202%7D%5C%5C%5C%5C%5Cdfrac%7B2x%7D%7B2%7D%3D%5Cdfrac%7B-6%7D%7B2%7D%5C%5C%5C%5Cx%3D-3)
Answer:
I don't love you
Step-by-step explanation:
yan po sana makatulong
Answer: $45451
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 25000
r = 3% = 3/100 = 0.03
n = 4 because it was compounded 4 times in a year.
t = 20 years
Therefore,
A = 25000(1+0.03/4)^4 × 20
A = 25000(1+0.0075)^80
A = 25000(1.0075)^80
A = $45451
In a fraction it will be 4 1/10