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choli [55]
3 years ago
6

A rectangle has a length of 12 mm and a width of 15 mm. Which statement best describes the change in the

Mathematics
1 answer:
laiz [17]3 years ago
3 0

ANSWER:

The new perimeter will be 1/3 times the perimeter of the original rectangle.

;p :D

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Gold Gym charges an initial fee of $142.50 plus a
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Answer:4months

Step-by-step explanation:

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2 years ago
I neeeddd help pleaase
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I got 65 for my answer. Hope that helps!
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3 years ago
Subtracting fractions with unlike denominators
lawyer [7]

Answer:

3/12 or simplified 1/4

Step-by-step explanation:

First make the denominators the same. We can make 12 the common denominator. To make 3/4 have a denominator do the following:

Multiply the numerator and denominator by 3 since 4x3=12. The new number becomes 9/12.

Then subtract:

9/12-6/12=3/12  The numerator subtracts while the denominator stays the same.

We can simplify 3/12 to 1/4

3 0
3 years ago
A number x increased by 8 is greater than 26
Julli [10]

Answer:

x+8<26

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3 0
3 years ago
Find dy/dx if f(x) = (x + 8)^3x.
vlabodo [156]
This is quite a complex problem. I wrote out a really nice solution but I can't work out how to put it on the website as the app is very poorly made. Still, I'll just have to type it all in...

Okay so you need to use a technique called logarithmic differentiation. It seems quite unnatural to start with but the result is very impressive.

Let y = (x+8)^(3x)

Take the natural log of both sides:

ln(y) = ln((x+8)^(3x))

By laws of logarithms, this can be rearranged:

ln(y) = 3xln(x+8)

Next, differentiate both sides. By implicit differentiation:

d/dx(ln(y)) = 1/y dy/dx

The right hand side is harder to differentiate. Using the substitution u = 3x and v = ln(x+8):

d/dx(3xln(x+8)) = d/dx(uv)

du/dx = 3

Finding dv/dx is harder, and involves the chain rule. Let a = x+ 8:

v = ln(a)
da/dx = 1
dv/da = 1/a

By chain rule:

dv/dx = dv/da * da/dx = 1/a = 1/(x+8)

Finally, use the product rule:

d/dx(uv) = u * dv/dx + v * du/dx = 3x/(x+8) + 3ln(x+8)

This overall produces the equation:

1/y * dy/dx = 3x/(x+8) + 3ln(x+8)

We want to solve for dy/dx, achievable by multiplying both sides by y:

dy/dx = y(3x/(x+8) + 3ln(x+8))

Since we know y = (x+8)^(3x):

dy/dx = ((x+8)^(3x))(3x/(x+8) + 3ln(x+8))

Neatening this up a bit, we factorise out 3/(x+8):

dy/dx = (3(x+8)^(3x-1))(x + (x+8)ln(x+8))

Well wasn't that a marathon? It's a nightmare typing that in, I hope you can follow all the steps.

I hope this helped you :)
8 0
3 years ago
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