52:44
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Answer:
The three points that lie on a line y = -2/5x with a slope -2/5 will be:
- (0, 0)
- (5, -2)
- (10, -4)
Please check the attached graph also.
Step-by-step explanation:
We know that the slope-intercept form of the line equation is
where m is the slope and b is the y-intercept
Given
slope = m = -2/5
We suppose the line passes through the origin.
so b = 0
substituting m = -2/5 and b = 0 in the slope-intercept form
y = -2/5x + 0
y = -2/5x
Thus, the equation of line with the slope m = -2/5 and passes through the origin (0, 0) will be:
y = -2/5x
As the equation of line passes through (0, 0), thus the point (0, 0) lies on the line.
Putting x = 0 in the equation y = -2/5x
y = -2/5 × (0)
y = 0
Thus, (0, 0) is the point which also passes through the line
Putting x = 5 in the equation y = -2/5x
y = -2/5 × 5
y = -2
Thus, (5, -2) is the point which also passes through the line
Now, putting x = 10 in the equation y = -2/5x
y = -2/5 × 10
y = -4
Thus, (10, -4) is the point which also passes through the line.
Thus, the three points that lie on a line y = -2/5x with a slope -2/5 will be:
- (0, 0)
- (5, -2)
- (10, -4)
Please check the attached graph also.
Answer: The asymptote of g(x) is the asymptote of f(x) shifted three units down.
Step-by-step explanation:
Answer:
6.4 units
Step-by-step explanation:
Distance² = (change in y)² + (change in x)²
Distance² = (4 - -1)² + (-8 - -4)²
Distance² = 25 + 16 = 41
Distance = = 6.403124237
The distance is 6.4 units (rounded off to nearest tenth)