Can someone help me for this
1 answer:
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According to the given question we have the following equations:
a. x2+3x-3=0
b. 3x2-7x=12
a. X2+3x-3=0
The first step to calculate this equation is:
Move the -3 to the other side:
So, the equation would be:
X2+3x=3
x2+3x=5x
Therefore:
5x=3
x=3/5
a. The value of x would be 3/5
b. 3x2-7x=12
First step:
Multyply 3x to 2, so:
3x*2=6x
Next we can proceed to calculate the value of x:
6x-7x=12
-x=12
x=-12
b. The value of x would be -12