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slava [35]
3 years ago
12

What is the slope of the line through (-4,-6) and (9,-6)

Mathematics
2 answers:
marusya05 [52]3 years ago
8 0

We can use the points (-4,-6) and (9,-6) to solve.

Slope formula: y2-y1/x2-x1

= -6-(-6)/9-(-4)

= 0/13

= 0

Hope This Helped! Good Luck!

Anit [1.1K]3 years ago
7 0

Answer:

0/13

Step-by-step explanation:

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The primes factors of 75 are 3 and 5
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3 years ago
Determine whether each of the following functions is even, odd, or neither even nor odd.
Illusion [34]

Answer:

A.) Even.

Step-by-step explanation:

If a function is an even function, then

F(-x) = f(x)

Also, if a function is an odd function, then, f(-x) = -f(x)

You are given the below function

f(x) = 1 + 3x^2 − x^4

Let x = 2

Substitute 2 for x in the function

F(x) = 1 + 3(2)^2 - (2)^4

F(x) = 1 + 3(4) - 16

F(x) = 1 + 12 - 16

F(x) = -3

Also, Substitute -2 for x in the function

F(x) = 1 + 3(-2)^2 - (-2)^4

F(x) = 1 + 3(4) - 16

F(x) = 1 + 12 - 16

F(x) = -3

Since f(-x) = f(x), we can conclude that

F(x) = 1 + 3x^2 - x^4 is even

5 0
3 years ago
There are 1,570 souvenir paperweights that need to be packed in boxes. Each box will hold 17 paperweights. How many boxes will b
arlik [135]

Answer:

93 boxes will be needed.

Step-by-step explanation:

Divide 1570 ÷ 17

This gives the answer 92.35

So 92 boxes won't be enough. 0.35 of a box itsn't helpful in the real world. So you need 93 boxes.

8 0
2 years ago
Help pleaseee i am awful at math
kupik [55]

Step-by-step explanation:

answer is B

use unitary method to solve it

6 0
2 years ago
Read 2 more answers
Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2
nlexa [21]

\bold{[ \ Answer \ ]}

\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}

\bold{[ \ Explanation \ ]}

  • \bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}

\bold{-------------------}

  • \bold{Rewrite}

\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}

  • \bold{Rewrite}

\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}

  • \bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}

\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}

  • \bold{Rewrite}

\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}

  • \bold{Simplify}

\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}

\boxed{\bold{[] \ Eclipsed \ []}}

3 0
3 years ago
Read 2 more answers
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