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Sindrei [870]
3 years ago
6

"The _____ of the Open Systems Interconnection (OSI) model generates the receiver’s address and ensures the integrity of message

s by making sure packets are delivered without error, in sequence, and with no loss or duplication."
Computers and Technology
2 answers:
Alona [7]3 years ago
8 0

Answer:

The Transport Layer

Explanation:

The <em>Open Systems Interconnection (OSI)</em> is a series of networking procedures or protocols contained in layers, precisely seven 7 layers. It ensures that standard protocols are used by different systems to communicate. The OSI model comprises of seven abstract layers, they are:

7. Application Layer

6. Presentation Layer

5. Session Layer

4. Transport Layer

3. Network Layer

2. Datalink Layer

1. Physical Layer

Every layer uniquely carries out a specific function and communicates with the layers below and above it. When a user receives data, the flow on the OSI model is from Layer 1 to Layer 7, but if the user is transmitting data, the flow is from Layer 7 to Layer 1.

<em>The transport layer</em> ensures that end-to-end communication is carried out efficiently. It is also responsible for error control and flow control. During data transmission, data is collected from the session layer and broken down into segments, these segments are now sent to the Network layer. While when data is received, the transportation layer reassembles the broken down segments into data and sends it to the session layer.

aleksklad [387]3 years ago
7 0

Answer:

The transport layer

Explanation: Layer 4, is the transport layer of the Open System Interconnection (OSI), that handles message transfer of data between end systems or hosts and ensures complete packets transfer.

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<h3>Writting the code:</h3>

<em>def checkSum(n):                    # Function definition</em>

<em>    total = 0                       # total variable which returns sum</em>

<em>    c = 0                           # counter variable which count the even position</em>

<em>    while(n!=0):                    # running a loop while n != 0</em>

<em>        r = int(n%10)               #breaking the number into digits</em>

<em>        c=c+1                       # increase counter</em>

<em>        if c%2==0:                  # if counter is even position then double the number </em>

<em>            r = r*2</em>

<em>            while(r!=0):                            # do the process</em>

<em>                total = total + int(r%10)</em>

<em>                r = int(r/10)</em>

<em>            n=int(n/10)    </em>

<em>        else:                       # if counter is odd position then simple add the digit </em>

<em>            total = total + r       # into total</em>

<em>            n=int(n/10)</em>

<em>    return total                    # in the last return the sum of digits</em>

<em># Driver code</em>

<em>n = int(input("Enter Number:"))         # asking user to enter the number </em>

<em>print(checkSum(n))                      # calling the function</em>

See more about python at brainly.com/question/18502436

#SPJ1

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