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nikdorinn [45]
2 years ago
14

Which sequences are geometric? Check all that apply. –2, –4, –6, –8, –10, … 16, –8, 4, –2, 1 –15, –18, –21.6, –25.92, –31.104, …

4, 10.5, 17, 23.5, 30, … 625, 125, 25, 5, 1, …
Mathematics
2 answers:
julsineya [31]2 years ago
6 0
16,-8,4,-2,1
-15,-18,-21.6,25.92,-31.104...
625,125,25,5,1
LiRa [457]2 years ago
5 0

Given sequences :

–2, –4, –6, –8, –10,...

16, –8, 4, –2, 1 , ......

–15, –18, –21.6, –25.92, –31.104, …

4, 10.5, 17, 23.5, 30, …

625, 125, 25, 5, 1, ….

Let us find the ratios.

–2, –4, –6, –8, –10,...

First sequence is just being decreased by -2. So it would be an Arithmetic sequence.

16, –8, 4, –2, 1 , ......

16/-8 = -2 and 4/-2 = -2.

In second sequence we got common ratio -2. Therefore, it's a geometric sequence.

–15, –18, –21.6, –25.92, –31.104, …

-15/-18 = 0.833

–21.6/ -18 = 0.833.

In second sequence we got common ratio 0.833. Therefore, it's a geometric sequence.

4, 10.5, 17, 23.5, 30, …

10.5/4 ≠ 17/10.5

Ratios are not same. So, it's not a geometric sequence.

625, 125, 25, 5, 1, ….

125/625 = 0.2 = 25/125.

<h3>In fourth sequence we got common ratio 0.2. Therefore, it's a geometric sequence.</h3>
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Answer:

(a) The height of the building is 60.06 m

(b) The distance AB is 139.43 m

Step-by-step explanation:

The given parameters are

Given that segment BT = segment AT + 29

By trigonometric ratios, we have;

cos∠ATC = CT/AT

cos∠BTC = CT/BT

Therefore, we have;

cos(40°) = CT/AT.................................(1)

cos(56°) = CT/BT = CT/(AT + 29).....(2)

cos(56°) = CT/(AT + 29)......................(3)

From equation (1)

CT = AT×cos(40°)

From equation (3)

AT×cos(56°) + 29 × cos(56°) = CT

Therefore;

AT×cos(40°) = AT×cos(56°) + 29 × cos(56°)

AT×cos(40°) - AT×cos(56°) =  29 × cos(56°)

AT×(cos(40°) - cos(56°)) =  29 × cos(56°)

AT = 29 × cos(56°)/(cos(40°) - cos(56°)) = 78.4 m

TC = CT = AT×cos(40°) = 78.4×cos(40°) = 60.06 m

The height of the building = 60.06 m

(b) BT = AT + 29 = 78.4 m + 29 m= 107.4 m

AB = AT×sin(∠ATC ) + BT×sin(∠BTC) = 78.4×sin(40°) + 107.4×sin(56°) =  139.43 m

The distance AB =  139.43 m.

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