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Lady bird [3.3K]
3 years ago
12

Juan brought 4 Tshirts and leather jacket. The T shirts were all the same price, and the price of the leather jacket was 6 times

the cost of one Tshirt. If the total cost of the T shirts and leather jacket was 209.00, what was the price of each T shirt?
Mathematics
1 answer:
Alex3 years ago
7 0

Let us say that:

x = the number of T shirts bought = 4

y = the number of leather jackets bought = 1

a = the price of the T shirts

b = the price of the leather jackets

 

With the given variables, we can say that the total cost is:

total cost = a x + b y

 

Since, b = 6 a, therefore:

total cost = a x + 6 a y

total cost = a (x + 6 y)

 

Since total cost is 209, therefore we can calculate for a since x and y are also given:

209 = a (4 + 6 * 1)

209 = a (10)

a = $20.9

 

<span>Therefore each T shirt cost $20.9</span>

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The given expression is presented as follows;

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\sum\limits _{n = 1}^{50} \left  k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}

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4 \times \sum\limits _{n = 1}^{50} \left  n^2 =  4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}

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4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3  \left (\dfrac{50(51) }{2} \right ).

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