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guajiro [1.7K]
3 years ago
12

What do geological principles tell you about inclusions?

Biology
2 answers:
Marizza181 [45]3 years ago
6 0

Answer:

the answer is c

Explanation:

kifflom [539]3 years ago
4 0

Answer:

C. Fragments are older than the rocks they are inside of.

Explanation:

Just took the test.

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Match the structural formula to the chemical formula for this substance
omeli [17]

Answer:

D.) HOCOOH

Explanation:

Structural formulas identify where the atoms/bonds within a molecule are located. Therefore, the atoms need to be listed in order of appearance (left to right). This makes the best answer D.) HOCOOH.

7 0
1 year ago
An epithelium with a single layer of tall cells would be classified as which type of epithelium?
lions [1.4K]

The epithelium with a single layer of tall cells is classified as simple cuboidal epithelium.

Epithelium is one of the major types of body tissue that line the outer surfaces of organs and blood vessels throughout the body.

The epithelium performs the following functions that include:

  • protection,
  • secretion,
  • secretion, absorption,
  • excretion,
  • filtration,
  • diffusion, and
  • sensory reception.

There are also different types of epithelium found in different parts of the body. A typical example is the simple cuboidal epithelium.

Simple cuboidal epithelium are single layered epithelium that are as tall as they are wide (cuboidal in shape).

They are found lining areas that are active in secretion and absorption.

Therefore, the epithelium with a single layer of tall cells is classified as simple cuboidal epithelium.

Learn more about epithelium here:

brainly.com/question/17301113

8 0
2 years ago
Gregor Mendel crossed true-breeding plants with green pea pods with true-breeding plants with yellow pea pods. The resulting F1
Alchen [17]

Answer:

A. Mendel observed green and yellow pea pods in a 3:1 ratio because the F1 generation was heterozygous.

Explanation:

The two true breeding plants in the parental population were homozygous (that is what true breeding means). Therefore, their cross would lead to all heterozygous offspring (see attached punnet square). Green is the dominant characteristic, so all F1 plants had a green phenotype, but Gg genotype.

The F1 cross would therefore be Gg x Gg. See attached punnet square.

The genotypes in the F2 generation are 1 GG: 2 Gg: 1 gg 1

Therefore, the phenotypic ratio is 3 green pea pods (Gg or GG): 1 yellow (gg)

Download pdf
4 0
3 years ago
Is it possible to have a knockout mutant plant that shows no visible phenotype that is different from the wild-type plant?
joja [24]

Answer:

Molecular genetic approaches to the study of plant metabolism can be traced back to the isolation of the first cDNA encoding a plant enzyme (Bedbrook et al., 1980), the use of the Agrobacterium Ti plasmid to introduce foreign DNA into plant cells (Hernalsteens et al., 1980) and the establishment of routine plant transformation systems (Bevan, 1984; Horsch et al., 1985). It became possible to express foreign genes in plants and potentially to overexpress plant genes using cDNAs linked to strong promoters, with the aim of modifying metabolism. However, the discovery of the antisense phenomenon of plant gene silencing (van der Krol et al., 1988; Smith et al., 1988), and subsequently co‐suppression (Napoli et al., 1990; van der Krol et al., 1990), provided the most powerful and widely‐used methods for investigating the roles of specific enzymes in metabolism and plant growth. The antisense or co‐supression of gene expression, collectively known as post‐transcriptional gene silencing (PTGS), has been particularly versatile and powerful in studies of plant metabolism. With such molecular tools in place, plant metabolism became accessible to investigation and manipulation through genetic modification and dramatic progress was made in subsequent years (Stitt and Sonnewald, 1995; Herbers and Sonnewald, 1996), particularly in studies of solanaceous species (Frommer and Sonnewald, 1995).

5 0
2 years ago
Checkpoints are points between phases of the cell cycle at which a cell determines whether all the requirements necessary for ea
Sedaia [141]

Answer:

The correct answer is - at the G1/S phase and G2/M phase.

Explanation:

The G1/S transition phase or checkpoint is a phase where the cell cycle arrested if during the evaluation of the DNA found damaged or other factors including external factors. Due to this evaluation and inadequate conditions, the cell will not enter the S phase.

The G2/M phase or transition phase is a checkpoint which takes place just before the M phase that ensures that all replicated DNA is not damaged before entering mitosis phase or M phase.

Thus, the correct answer is - at the G1/S phase and G2/M phase.

5 0
3 years ago
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