Let

, where

and let

be any real constant.
Given this definition of scalar multiplication, we can see right away that there is no identity element

such that

because
Answer:
455ways
Step-by-step explanation:
This is expressed as 15 C 3 ( C- combination)
The concept of combination is used when we talk about selection.
Now we are selecting 3 from a sample of 15
15 C 3 = 15! / (15-3)! 3! = 15 ×14×13×12!/12!×3×2
= 5 × 7 × 13 = 455ways
William payed $8.55 at the discount price
X=75
y=75
z=105
as you do 42 + 63=105
Answer:
53 packages
Step-by-step explanation: