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amm1812
3 years ago
9

X/15=y/20=z/18 và 2x+3y-2

Mathematics
1 answer:
Scilla [17]3 years ago
3 0

Answer:

Chào em, em hãy xem lời giải dưới đây nhé!

Lời giải:

Vì  nên

Áp dụng tính chất của dãy tỉ số bằng nhau ta có

Hope I` Helpede` Momo papa

Step-by-step explanation:

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Here is a sequence of numbers:
Kazeer [188]

Answer:

It is a fibonacci sequence

Step-by-step explanation:

The Fibonacci Sequence is the series of numbers: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34 etc

4 0
2 years ago
Graph quadrilateral ABCD and find the most precise name (square, rectangle,
Pavlova-9 [17]

Answer:

Kite

Step-by-step explanation:

To graph quadrilateral with points:

A(-1,-2)

B(5,1)

C(-3,1)

D(-1,4)

Thus, we graph the the given points and join the corners. The quadrilateral formed has the following features:

Measure of segment AB= Measure of segment BD = 6.708 units

Measure of segment AC= Measure of segment CD = 3.605 units

Thus, adjacent pair of sides of the quadrilateral are congruent.

Major diagonal BC cuts the minor diagonal AD at point E such that:

Measure of segment AE= Measure of segment ED = 3 units

m∠AEB = m∠DEB = 90°

Thus, major diagonal is a perpendicular bisector of the minor diagonal.

The above stated features fulfills the criterion of a kite.

Hence, the given quadrilateral ABCD is a kite.

8 0
2 years ago
50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle
aalyn [17]

Answer:

EF=4\sqrt{3}

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A_{\text{rect}}=8(6)=48\text{ cm}^2

The area of the triangle is 1/4 of this. Therefore:

\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

\displaystyle 12=\frac{1}{2}(DE)(DF)

Since DE = DF:

24=DF^2

Thus:

DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

(DE)^2+(DF)^2=(EF)^2

Therefore:

(2\sqrt6)^2+(2\sqrt6)^2=EF^2

Square:

24+24=EF^2

Add:

EF^2=48

And finally, we can take the square root of both sides:

EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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