Answer:
Step-by-step explanation:
Given that:

This implies that the level curves of a function(f) of two variables relates with the curves with equation f(x,y) = c
here c is the constant.

By cross multiply



From (2); let assume that the values of c > 0 likewise c < 100, then the interval can be expressed as 0 < c <100.
Now,

This is the equation for the family of the eclipses centred at (0,0) is :


Therefore; the level of the curves are all the eclipses with the major axis:
and a minor axis
which satisfies the values for which 0< c < 100.
The sketch of the level curves can be see in the attached image below.
Answer:THIS TOOK ME FOREVER BUT WAS WORTH IT
1)1 1/7 times 1 3/4=2
2)8 1/3 times 3/5=5
3)4 3/8 times 1 2/3= 7 7/24
4)5 1/2 times 3 1/3=18 1/3
5)7 1/5 times 2 1/6=10 3/14
6)2/3 times 4/15=8/4
7)2 2/5 times 1 1.4=27 9/25
8)4 2/5 times 10=44
9)26 times 2 1/2=65
10)6 times 3 2/3=22
11)6 1/4 times 1 5/7=10 5/7
12)3 1/3 times 2 3/5=8 2/3
13)4 1/2 times 4 2/3=21
14)5 5/8 times 1 5/9=8 2/4
Step-by-step explanation:
The steps matter on the size of the number.
Answer: Each have to sell 91 candy bars to have the same amount of money.
Step-by-step explanation: Suppose x represents the amount of candy bars.
Team A already have $165 and they are selling each candy bar for $2. The mathematical equation that represents the amount of money they have is
A: 165 + 2x
Team B initially has $74 and will sell each candy bar for $3. Then, the mathematical equation representing their amount of money is
B: 74 + 3x
So, to have the same amount of money:
165 + 2x = 74 + 3x
x = 165 - 74
x = 91
<u>Teams A and B will have the same amount of money when each of them </u><u>sell 91 candy bars</u>.
I believe it's 200 feet tall.
40/9.6 = x/48
Use laws of proportions to solve for x