If an is a5
and
an-1 is a4
then using your recursive formula for an arithmetic sequence
an=an-1 +d
then
a5=a4+d
now, a4 =6 and common difference "d" is d=-11
hence
a5=6 -11
6-11= -5
any questions?
A^2+b^2=c^2 so 4(4) +3(3) is 16+9= 25 and the square root of that is 5.
Okay the answer is 69 because 81-2 is 69
Answers:
first term = 37
second term = 46
third term = 55
fourth term = 64
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Explanation:
Start at 37. Add 9 to this term to get the second term. Add 9 to that result to get the next term, and so on.
first term = 37
second term = 37+9 = 46
third term = 46+9 = 55
fourth term = 55+9 = 64
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The nth term formula is
a(n) = 9n+28
It can be found by plugging a = 37 and d = 9 into the general form
a(n) = a + d*(n-1)
