Answer:
void printC()
{
int i, j;
for (i = 0; i < 4; i++) //i indicate row number. Here we have 5 rows
{
printf("C"); //print C for every row
for (j = 0; j < 6; j++) //j indicate column number. Here we have 7 Rows
{
if (i == 0 || i == 4) //For first and last row
printf("C"); //print 'CCCCCCC'
else if (i = 1|| i= 3) //for Second forth row
printf("C + +"); //print 'C + +'
else if (i = 2) For second row
printf("C +++++"); //print 'C +++++'
else
continue; //to jump to next iteration
}
printf("\n"); // print in next line
}
}
Answer:
Explanation:
#include <iostream>
using namespace std;
int costdays(int);
int costhrs(int,int);
int main()
{
int dd,hh,mm,tmph,tmpd,tmpm=0;
int pcost,mcost=0;
cout<<"Enter Parking time" << endl;
cout<<"Hours: ";
cin>>hh;
cout<<"Minutes: ";
cin>>mm;
if (mm>60)
{
tmph=mm/60;
hh+=tmph;
mm-=(tmph*60);
}
if (hh>24)
{
tmpd=hh/24;
dd+=tmpd;
hh-=(tmpd*24);
}
if ((hh>4)&&(mm>0))
{
pcost+=costdays(1);
}
else
{
mcost=costhrs(hh,mm);
}
cout<<"Total time: ";
if (dd>0)
{
cout<<dd<<"days ";
pcost+=costdays(dd);
}
pcost+=mcost;
cout<<hh<<"h "<<mm<<"mins"<<endl;
cout<<"Total Cost :"<<pcost<<"Won";
return 0;
}
int costdays(int dd)
{
return(dd*25000);
}
int costhrs(int hh,int mm)
{
int tmpm, tmp=0;
tmp=(hh*6)*1000;
tmp+=(mm/10)*1000;
tmpm=mm-((mm/10)*10);
if (tmpm>0)
{
tmp+=1000;
}
return(tmp);
}
Answer:
A crowd because it makes more sense tho i could be wrong
Answer:
def print_popcorn_time(bag_ounces):
if bag_ounces<3:
print("Too Small")
elif bag_ounces>10:
print("Too Large")
else:
total = 6*bag_ounces
print('{} seconds'.format(total))
Explanation:
Using Python programming language
The function is defined to accept a single parameter
Using a combination of if/elif/else statements, the approprite message is displayed when the function is called
