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Mashutka [201]
4 years ago
8

I need to know 7 and 8

Mathematics
2 answers:
Harman [31]4 years ago
5 0
Yes the other person that sent u the answers is helpful
insens350 [35]4 years ago
4 0
7:
5x12=60
8x14=112
60+112=172

8:
12X28=336

hope this helps :)
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A 98% confidence interval for a proportion is found to be (0.62, 0.68).
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Answer:

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Step-by-step explanation:

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Christina went to the salon and had 5/8 of an inch of hair cut off. The next day she went back and asked for another 5/8 of an i
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likoan [24]

Answer:

\boxed{66}

Step-by-step explanation:

if \: the \: question \: is \: f[g(4)] \\ then \: at \: first \: solve \: for \: g(4) \\ g(4) =  {4}^{2}  \\ f[g(4)]  = 4( {4}^{2} ) + 2 \\ f[g(4)]  = 4(16) + 2 \\ f[g(4)]  =64 + 2 \\   f[g(4)]  =  \boxed{66}

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3 years ago
The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches. Men the same
masha68 [24]

Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

Step-by-step explanation:

Let x and y area the random variable that represents the heights of women and men.

Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.

i.e. \mu_1 = 64   \sigma_1=2.7

Since , z=\dfrac{x-\mu}{\sigma}

Then, z-score corresponds to  a woman 6 feet tall (i.e. x=72 inches).

[∵  1 foot = 12 inches , 6 feet = 6(12)=72 inches]

z=\dfrac{72-64}{2.7}=2.96296296\approx2.96

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.

i.e. \mu_2 = 69.3   \sigma_2=2.8

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).

[∵  1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

z=\dfrac{70-69.3}{2.8}=0.25

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

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b i think

Step-by-step explanation:

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