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3 years ago

HELP ME

Mathematics

2 answers:

BartSMP [9]3 years ago

8 0

Answer:

7.07?

Step-by-step explanation:

Mkey [24]3 years ago

8 0

Answer:

7.07 inches

Step-by-step explanation:

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A solid right pyramid has a square base with an edge

Dovator [93]

Answer:

$sah units^{3}$ represents the volume.

Step-by-step explanation:

Given

Length of edge as 's' and height as 'h'

Let 'a' be the area of base

Now, in the other three options the unit is only units and in sah the unit is $units^{3}$

So for any Volume we always have three dimensions that is Length, Breadth and Height.

so $Volume = L\times B\times H$

∴ $= meter\times meter\times meter$

∴ $= meter^{3}$

That is like $unit\times unit\times unit$

which is $units^{3}$

6 0

4 years ago

Write the general equation for the circle that passes through the points (1, 1), (1, 3), and (9, 2).

Burka [1]

Step-by-step explanation:

As we know that

The circle center is equidistant from all three points, the distance being the circle radius.

Any point equidistant from two points must lie on the perpendicular bisector of the line segment which join those two points.

Which is, on the line through the midpoint of the line segment, perpendicular to the line segment.

The perpendicular bisector of the line segment joining the points (1, 1) and (1, 3) will be:

$\:y=\:\frac{1+3}{2}=\frac{4}{2}=2$

The perpendicular bisector of the line segment joining the points (1, 3), and (9, 2) will be:

$x=\:\frac{1+9}{2}=\frac{10}{2}=5$

These intersect at the center of the circle (5, 2).

The distance between (1, 1) and (5, 2) will be:

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$\mathrm{The\:distance\:between\:}\left(1,\:1\right)\mathrm{\:and\:}\left(5,\:2\right)\mathrm{\:is\:}$

$=\sqrt{\left(5-1\right)^2+\left(2-1\right)^2}$

$=\sqrt{4^2+1}$

$=\sqrt{16+1}$

$=\sqrt{17}$

So the equation of the circle can be written as:

$\left(x-5\right)^2+\left(y-2\right)^2=17$

$x^2-10x+y^2+29-4y=17$

$x^2-10x+y^2-4y+12\:=0$

$x^2+y^2-10x-4y+12=0$

8 0

3 years ago

Please help me solve this, and show your work

zlopas [31]

$6r+5=11r\ \ \ \ |\text{subtract 6r from both sides}\\\\5=5r\ \ \ \ |\text{divide both sides by 5}\\\\\boxed{r=1}\\-------------------------\\\dfrac{2x-4}{2}=6x+3\\\\\dfrac{2x}{2}-\dfrac{4}{2}=6x+3\\\\x-2=6x+3\ \ \ \ \ |\text{add 2 to both sides}\\\\x=6x+5\ \ \ \ |\text{subtract 6x from both sides}\\\\-5x=5\ \ \ \ \ |\text{divide both sides by -5}\\\\\boxed{x=-1}$

6 0

4 years ago

Which value of x makes the open sentence true? 10 +m2x< 15x-20? 0, 1, 2,3

Zielflug [23.3K]

x=3 if the m was a typo, idk what that means

3 0

3 years ago

cho hàm số y = f(x) có đạo hàm liên tục trên R thỏa mãn 2f(2x)+f(1-2x) = 12x2 víu mọi x thuộc R . Phương trình tiếp tuyến của đồ

Nina [5.8K]

Answer:

ask in english

Step-by-step explanation:

then I can help u

6 0

3 years ago