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3 years ago

I need help with before 9

Mathematics

2 answers:

Lapatulllka [165]3 years ago

7 0

Answer:

1) p = how much he was paid per lawn

2) 4p = how much he was paid for 4 lawns

3) 4p = 24, then p = $6

4) 45-d = 21, d = $24

Westkost [7]3 years ago

3 0

Answer:

There is no 9 on the paper.

Step-by-step explanation:

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a tourist drove his car for the total of 17.5 hours while on a 3-day vacation on the first day he drove 4.5 hours in the second

AleksAgata [21]

Answer:

1.75 hours

Step-by-step explanation:

Time for day 1 : 4.5 hrs

Time for day 2: (4.5 ×2.5)

Time for day 3: let it be denoted by a variable ,say T.

Total Time= 17.5

(Time for day 1 ) + (Time for day 2) +(Time for day 3) =17.5

4.5 + (4.5×2.5) + T = 17.5

4.5+11.25+T =17.5

15.75+T=17.5

T=17.5-15.75

T= 1.75

7 0

3 years ago

Step by step<br> Please urgent

kotegsom [21]

Answer:

Below in bold.

Step-by-step explanation:

1) ( a^2 + b^2 = (a + b)^2 - 2ab

= 29 - 2(6)

= 29-12

= 17.

2). (x - y)^2 = x^2 + y^2 - 2xy

so 20 = 18 - 2xy

2xy = 18-20 = -2

xy = -1.

3). 1/x + x = 7

(1/ x + x)^2 = 1/x^2 + x^2 +x/x + x/x

= 1/x^2 + x^2 + 2

But(1/x + x)^2 = 7^2 = 49

so 1/x^2 + x^2 + 2 = 49

so 1/x^2 + x^2 = 49 - 2 = 47.

6 0

3 years ago

del puerto de cabo San Lucas México salen dos barcos el barco México 1,navega con una trayectoria de x+y=88;el barco México 2 na

Margarita [4]

Pls in english!!!!!!!?????

8 0

3 years ago

What is the length of the major axis of the ellipse (x-7)^2/4+(y+3)^2/16=1

yuradex [85]

$\bf \begin{array}{llll}
\cfrac{(x-{{ h}})^2}{{{ a}}^2}+\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1\\\\ \cfrac{(x-{{ h}})^2}{{{ b}}^2}+\cfrac{(y-{{ k}})^2}{{{ a}}^2}=1
\end{array}\quad 
\begin{cases}
\textit{major axis}=a+a\\
a=\textit{the larger denominator}\\
b=\textit{smaller denominator}
\end{cases}\\\\
-----------------------------\\\\
\cfrac{(x-7)^2}{4}+\cfrac{(y+3)^2}{16}=1\implies \cfrac{(x-7)^2}{2^2}+\cfrac{(y+3)^2}{4^2}=1\quad 
\begin{cases}
a=4\\
b=2
\end{cases}$

6 0

2 years ago

Heyy can you help me out on this question please

defon

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2}-4ac } }{2a}$

b = coefficient of x term = 5
a = coefficient of squared term = 1
c = constant term = 7

Using the values, we get:

$x= \frac{-5+- \sqrt{25-4(1)(7)} }{2(1)} \\ \\ 
x= \frac{-5+- \sqrt{-3} }{2}$

So, the correct answer to this question are option E and F

8 0

3 years ago