Answer:
-2
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
4(3+c)+c=c+4
(4)(3)+(4)(c)+c=c+4(Distribute)
12+4c+c=c+4
(4c+c)+(12)=c+4(Combine Like Terms)
5c+12=c+4
5c+12=c+4
Step 2: Subtract c from both sides.
5c+12−c=c+4−c
4c+12=4
Step 3: Subtract 12 from both sides.
4c+12−12=4−12
4c=−8
Step 4: Divide both sides by 4.
4c
4
=
−8
4
c=−2
I don't think it can becauze of u count the squares and try 2 plan out the triangle u cant or i should say me i cant see a triangle being formed
Answer:
This means that after going around the unit circle once (2π radians), both functions repeat. So the period of both sine and cosine is 2π . Hence, we can find the whole number line wrapped around the unit circle.
Step-by-step explanation:
The zeroes of <span>f(x) = x^5-12x^2+32x can be found by factoring,
</span><span>f(x) = x^5-12x^2+32x=(x-8)(x-4)
By the zero product theorem, (x-8)=0 or (x-4)=0 which means
x=8 or x=4.
So the zeroes of f(x) are S={4,8}</span>
U^2(2u+3)+7(2u+3)
(u^2+7)(2u+3)
