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alexgriva [62]
3 years ago
10

Plz help ZOOM IN TO SEE IT CLEAR

Mathematics
1 answer:
spin [16.1K]3 years ago
4 0
2nd option , i hope that helps
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What is the 100th term in the list?1017243138
Studentka2010 [4]

the sequence starts at 10 and increases by 7 each time, thefore a possible sequence identification is:

\begin{gathered} a_n=7n+3 \\ \text{Let's verify:} \\ a_1=7(1)+3=7+3=10 \\ a_2=7(2)+3=14+3=17 \\ a_3=7(3)+3=21+3=24 \\ \text{and so on} \\ \text{.} \\ \text{.} \\ \text{.} \end{gathered}

Therefore, the 100th term is:

a_{100}=7(100)+3=700+3=703

3 0
1 year ago
Waqas wishes to distribute 128 bananas and also 176 apples equally among a certain number of children. find the highest number o
atroni [7]
Answer:
The maximum number of children = 16 

Explanation:
The greatest number of students who can get the fruit in this way (equally) will be equal to the highest common factor between the number of bananas and the number of apples.

Number of bananas = 128 = 2 * 2 * 2 * 2 * 2 * 2 * 2
number of apples     = 176 = 2 * 2 * 2 * 2 *11

We can note that:
the highest common factor = 2 * 2 * 2 * 2 
the highest common factor = 16

This means that the maximum number of children to get both equally is 16

Hope this helps :)
7 0
4 years ago
The measure ∠BQS of is 80°. What is the m∠NQS? 42° 48° 128° 32°
fomenos

Answer:

m<NQS = 32°

Step-by-step explanation:

Given:

m<BQS = 80°

m<BQN = 48°

Required:

m<NQS

SOLUTION:

Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.

Therefore:

m<BQN + m<NQS = m<BQS (angle addition postulate)

48° + m<NQS = 80° (substitution)

m<NQS = 80 - 48° (Subtraction of 48 from each side)

m<NQS = 32°

3 0
3 years ago
Read 2 more answers
Solve 10% off $29<br><br><br> pls!!!!!!!!!!!!!!!!!!!! help<br><br> 20points
kompoz [17]

Answer: the answer is 2.9 US$

4 0
3 years ago
Read 2 more answers
Triangle DEF is an isosceles, so AngleDEF Is-congruent-toAngleDFE. A horizontal line has points C, F, E, G. 2 lines extend from
zaharov [31]

Answer:

\angle CFD =105^o

Step-by-step explanation:

Given

\angle D FE = \angle DE F = 75^o

See attachment

Required

Determine the measure of \angle CFD

\angle CFD and \angle DFE are on a straight line.

So:

\angle CFD + \angle DFE = 180^o --- angle on a straight line

Substitute known values

\angle CFD + 75^o = 180^o

Collect like terms

\angle CFD =- 75^o + 180^o

\angle CFD =105^o

5 0
3 years ago
Read 2 more answers
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