Answer:
Answer is: Keq = [CO₂].
Explanation:
Balanced chemical reaction: CaCO3(s) ⇄ CaO(s) + CO₂(g).
The equilibrium constant (Keq) is a ratio of the concentration of the products to the concentration of the reactants.
Pure liquids (shown in chemical reactions by appending (l) to the chemical formula) and solids (shown in chemical equations by appending (s) to the chemical formula) not go in to he equilibrium constant expression, only gas state (shown in chemical reactions by appending (g) to the chemical formula) reactants and products go in to the equilibrium constant expression
Answer:
7 cm^3
Explanation:
Density = Mass/Volume
5 = 35/x
multiply both sides by x to get
5x = 35
then divide by 5
so x = 7 cm^3
Answer: Adiabatic process is a process in which <u>heat</u> is constant
Explanation:
The processes in which temperature remains constant is called isothermal process.
The process in which Volume remains constant is called isochoric process.
The process in which pressure remains constant is called isobaric process.
The process in which no heat is gained or lost by the system, Hence heat remains constant is called as adiabatic process.
Thus option d) heat is correct
The HONC 1234 rule is a way to remember the bonding tendencies of hydrogen, oxygen, nitrogen, and carbon atoms in molecules. Hydrogen tends to form one bond, oxygen two, nitrogen three and carbon four.
Answer:
34.3 g
Explanation:
Step 1: Write the balanced equation
2 CH₃CH₂OH ⇒ CH₃CH₂OCH₂CH₃ + H₂O
Step 2: Calculate the moles corresponding to 50.0 g of CH₃CH₂OH
The molar mass of CH₃CH₂OH is 46.07 g/mol.
50.0 g × 1 mol/46.07 g = 1.09 mol
Step 3: Calculate the theoretical moles of CH₃CH₂OCH₂CH₃ produced
The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 1.09 mol = 0.545 mol.
Step 4: Calculate the real moles of CH₃CH₂OCH₂CH₃ produced
The percent yield of the reaction is 85%.
0.545 mol × 85% = 0.463 mol
Step 5: Calculate the mass corresponding to 0.463 moles of CH₃CH₂OCH₂CH₃
The molar mass of CH₃CH₂OCH₂CH₃ is 74.12 g/mol.
0.463 mol × 74.12 g/mol = 34.3 g
