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ra1l [238]
3 years ago
12

Copper (II) oxide reacts with carbon to form Copper metal and carbon dioxide. If 365 grams of Copper (II) oxide were reacted wit

h excess carbon, how much carbon dioxide would be produced?
a. 101 g
b. 0.349 g
c. 289 g
d. 56 g
Chemistry
1 answer:
Annette [7]3 years ago
7 0
The balanced reaction formula is 2CuO + C = 2Cu + CO2. The change the 365 g to mole: 365/79.5=4.6 mol. So you can get 2.3 mol CO2. The mass is 2.3*44=101 g. So the answer is a.
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Explanation:

Hello there!

In this case, according to the given redox reaction, we rewrite it as a convenient first step:

2NO + 3MnO_2 + 4H^+ \rightarrow 2NO_3^- + 3Mn^{2+} + 2H_2O

Next, we assign the oxidation numbers as follows:

2N^{2+}O^{2-} + 3Mn^{4+}O^{-2}_2 + 4H^+ \rightarrow 2(N^{5+}O^{2-}_3)^- + 3Mn^{2+} + 2H^+_2O^{2-}

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).

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3 years ago
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<span>write out the balance equation
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equation is deltaHneutraliztion=q/Moles of limiting reagent H3PO4 is limiting reagent because lowest moles, and is used up first
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Notice we had to convert J to kj,</span>
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