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ra1l [238]
3 years ago
12

Copper (II) oxide reacts with carbon to form Copper metal and carbon dioxide. If 365 grams of Copper (II) oxide were reacted wit

h excess carbon, how much carbon dioxide would be produced?
a. 101 g
b. 0.349 g
c. 289 g
d. 56 g
Chemistry
1 answer:
Annette [7]3 years ago
7 0
The balanced reaction formula is 2CuO + C = 2Cu + CO2. The change the 365 g to mole: 365/79.5=4.6 mol. So you can get 2.3 mol CO2. The mass is 2.3*44=101 g. So the answer is a.
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Describe how the size of the sun compares to the sizes of the other stars.
alina1380 [7]

Answer:

The sun's circumference is about 2,713,406 miles (4,366,813 km). It may be the biggest thing in this neighborhood, but the sun is just average compared to other stars. Betelgeuse, a red giant, is about 700 times bigger than the sun and about 14,000 times brighter.

Explanation:

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6 0
2 years ago
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wolverine [178]
I think to measure the age of the rock 
6 0
3 years ago
A 150.0 mL sample of a 1.50 M solution of CuSO4 is mixed with a 150.0 mL sample of 3.00 M KOH in a coffee cup calorimeter. The t
svp [43]
Mols CuSO4 = M x L = 1.50 x 0.150 = 0.225 
<span>mols KOH = 3.00 x 0.150 = 0.450 </span>
<span>specific heat solns = specific heat H2O = 4.18 J/K*C </span>

<span>CuSO4 + 2KOH = Cu(OH)2 + 2H2O </span>
<span>q = mass solutions x specific heat solns x (Tfinal-Tinitial) + Ccal*deltat T </span>
<span>q = 300g x 4.18 x (31.3-25.2) + 24.2*(31.3-25.2) </span>
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5 0
3 years ago
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1 point
Elina [12.6K]

Answer:

84672 J

Explanation:

From the question given above, the following data were obtained:

Height (h) = 72 m

Combined mass (m) = 120 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E) =?

We can obtain the energy by using the following formula:

E = mgh

Where

E => is the energy.

g => is the acceleration due to gravity

m => is the mass.

h => is the height.

E = 120 × 9.8 × 72

E = 84672 J

Thus, the energy is 84672 J

6 0
3 years ago
What is the mass ratio of aluminum to oxygen in aluminum oxide, Al2O3?
liubo4ka [24]

Answer:

9 : 8

Explanation:

Aluminum oxide has the following formula Al₂O₃.

Next, we shall determine the mass of Al and O₂ in Al₂O₃. This can be obtained as follow:

Mass of Al in Al₂O₃ = 2 × 27 = 54 g

Mass of O₂ in Al₂O₃ = 3 × 16 = 48 g

Finally, we shall determine the mass ratio of Al and O₂. This can be obtained as follow:

Mass of Al = 54 g

Mass of O₂ = 48 g

Mass of Al : Mass of O₂ = 54 : 48

Mass of Al : Mass of O₂ = 54 / 48

Mass of Al : Mass of O₂ = 9 / 8

Mass of Al : Mass of O₂ = 9 : 8

Therefore, the mass ratio of Al and O₂ in Al₂O₃ is 9 : 8

5 0
3 years ago
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