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vivado [14]
3 years ago
13

The phases of the moon repeat in a cycle about every _______ days. *

Chemistry
1 answer:
DaniilM [7]3 years ago
8 0

Answer:

The moon revolves around the Earth once every 29.5 days

Explanation:

So around 30 days.

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The decomposition of water into hydrogen gas Hy and oxygen gas Oz can be modeled by the balanced chemical equation
ASHA 777 [7]

Answer:

D. ) 2H2O - 2H2 + O2

3 0
3 years ago
If a muriatic acid solution has a pH of 2.50, what is the hydronium ion concentration (hydronium ion concentration is also the m
Irina18 [472]

Answer:

  • [H₃O⁺] = 0.032 M

Explanation:

The acidity of a solution is measured by its pH, which is the logarithm of the inverse of the molar concentration of hydronium (H₃O⁺) ions:

  • pH = log 1 / [H₃O⁺] = - log [H₃O⁺]

When you know the pH value you can find hydronium concentration using the antilogaritm function:

pH=-log[H_3O^{+}]\\ \\ {[H_3O^+]}=10^{-pH}\\ \\ {[H_3O^+]}=10^{-2.50}\\ \\ {[H_3O^+]}=0.0032

The unit of molar concentration is M.

To prove your answer you can take the logarithm of 0.0316:

  • log (0.0032) ≈ 2.500

5 0
3 years ago
What is 6.9 x 10^-3 in standard form?
Maslowich

Answer:

0.0069

Explanation:

When converting between scientific notation try to remember that moving the decimal place to the left is positve and to the right is negative

Since you are changing from scientific to standard you will need to move to the left from the decimal point, making your answer 0.0069

4 0
3 years ago
Question in photo! Will give brainliest
Jlenok [28]
To be honest, I can’t really see the question. So please next time just type it out lol
7 0
2 years ago
The enthalpy of a pure liquid at 75oC is 100 J/mol. The enthalpy of the pure vapor of that substance at 75oC is 1000 J/mol. What
pentagon [3]

Answer:

900 J/mol

Explanation:

Data provided:

Enthalpy of the pure liquid at 75° C = 100 J/mol

Enthalpy of the pure vapor at 75° C = 1000 J/mol

Now,

the heat of vaporization is the the change in enthalpy from the liquid state to the vapor stage.

Thus, mathematically,

The heat of vaporization at 75° C

=  Enthalpy of the pure vapor at 75° C - Enthalpy of the pure liquid at 75° C

on substituting the values, we get

The heat of vaporization at 75° C = 1000 J/mol - 100 J/mol

or

The heat of vaporization at 75° C = 900 J/mol

8 0
3 years ago
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