A cylinder contains 27.0 L of oxygen gas at a pressure of 1.7 atm and a temperature of 285 K . Part A How much gas (in moles) is

Question

grigory [225]

3 years ago

14

A cylinder contains 27.0 L of oxygen gas at a pressure of 1.7 atm and a temperature of 285 K . Part A How much gas (in moles) is

in the cylinder? Express your answer using two significant figures.

Chemistry

1 answer:

MA_775_DIABLO [31] · Answer 1 · 2022-08-02T11:09:40+03:00

MA_775_DIABLO [31]3 years ago

7 0

Answer:

$n=2.0mol$

Explanation:

Hello.

In this case, we should use the ideal gas equation in order to compute the the moles of oxygen at the given conditions of 27.0 L, 1.7 atm and 285 K as shown below:

$PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.7atm*27.0L}{0.082\frac{atm*L}{mol*K}*285K}\\ \\n=2.0mol$

Best regards.