Please help me on this question.

where would an imaginary line need to be drawn to reflect across an axis of symmetry so that a regular pentagon can carry onto i

irina [24]

Answer:

An imaginary line would need to be drawn at any angle to the center of the side opposite the angle to reflect across an axis of symmetry so that a regular pentagon can carry onto itself. Hope this answer helps.

5 0

3 years ago

Marina spent $13.50 at the grocery store. She bought pears, kiwis, and pineapples. Pears cost $0.50 each, pineapples cost $1.50

kiruha [24]

Answer:

Number of pineapples = 10

Number of pears = 10 + 9 = 19

Number of kiwis = 10 - 2 = 8

Step-by-step explanation:

Money = $ 13.5

Cost of a pear = $ 0.5

Cost of a pineapple = $ 1.5

Cost of a kiwi = $ 0.3

let the number of pineapple = p

Number of pears = p + 9

Number of kiwis = p - 2

Cost is

0.5 (p + 9) + 0.15 p + 0.3 (p - 2) = 13.5

0.5 p + 4.5 + 0.15 p + 0.3 p - 0.6 = 13.5

0.95 p = 9.6

p = 10

So, number of pineapples = 10

Number of pears = 10 + 9 = 19

Number of kiwis = 10 - 2 = 8

4 0

3 years ago

Read 2 more answers

A croissant shop produces two products: bear claws (B) and almond filled croissants (C). Each bear claw requires 6 oz of flour,

Kruka [31]

Answer:

letter A: B = 400; C = 1000; Max Z = $380

Step-by-step explanation:

bear claws (B) need 6 oz of flour (f), 1 oz of yeast (y), 2 ts of paste (p)

croissants (C) need 3 oz of flour (f), 1 oz of yeast (y), 4 ts of paste (p)

putting that information in equations, we have:

B = 6f + y + 2p

C = 3f + y + 4p

The total number of resources (R) are:

R = 6600f + 1400y + 4800p

Let's call M our total profit, "k1" the number of B produced and "k2" the number of C produced.

So, we can state that:

M = k1*0.2 + k2*0.3

The number of resources R2 will demand is calculated like this:

R2 = k1*B + k2*C = (6k1+3k2)f + (k1+k2)y + (2k1+4k2)p

using R2 and R, we can make some inequations:

6k1+3k2 <= 6600 -> 2k1+k2 <= 2200

k1+k2 <= 1400

2k1+4k2 <= 4800 -> k1+2k2 <= 2400

if we try to maximize k2 (as it worths more), we will have k1 = 0 and k2 = 1200 (limited by p), but looking at the resources R, we will still have resources to use (f and y). Looking at B and C expressions, we see that removing one C gives enough 'p' to make 2 B, which is a good trade (as 2B worths 0.4 cents, and 1C worths 0.3 cents). we have 200 'y' remaining, so doing this 200 times give us k1 = 400 and k2 = 1000, and the only resource remaining will be some of 'f'.

calculating the profit M, we have:

M = 400*0.2 + 1000*0.3 = 380$

the right answer is letter A.

3 0

3 years ago

Can u HELP me on all

Alekssandra [29.7K]

How many are there because there is no pic

3 0

3 years ago

Gideon is painting all sides of a square pyramid-shaped decoration at the top of his fence post. A net of the decoration is show

frez [133]

Gideon is painting all sides thus we find the overall area of the square pyramid given in the picture. A square pyramid is a polyhedron that consists of a square and 4 triangles. To solve the area that Gideon will have to paint, we can calculate the area of the square and the area of the triangles then add these two values of area. We proceed as follows:
Area of the square = s^2 where s is the measure of the side
Area of the square = 4^2 = 16 in^2

Area of the triangle= 1/2 bh where b is the base of the triangle and h is height of the triangle
Area of the triangle = 1/2 (4) (5) = 10 in^2
We multiply the area of the triangle to four in order to obtain the total area of the triangles.
Total area of the triangles = 4 x 10 = 40 in^2

We then add the two areas,
Total Area = 16 + 40 = 56 in^2

Thus the total area that Gideon will have to paint for one square pyramid is 56 in^2.

6 0

3 years ago