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3 years ago

How does the graph of g(x) = x+ 4 compare with the graph of the parent function, fx) = x?

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

7 0

Answer:

It is moved 4 units up.

Step-by-step explanation:

If you have trouble visualizing it, there is an app i recommend, its call Desmos.

olasank [31]3 years ago

5 0

Answer:

g(x) is a translation of f(x) up 4 units

Step-by-step explanation:

We see that the difference between g(x) and f(x) is that g(x) has an additional + 4.

According to transformations, we know that this will be a translation of some sort. Since the + 4 is to the entire function, we know that it is a vertical translation. And, since it is + 4 and not - 4, we know that this is a translation up 4 units.

Thus, g(x) is a translation of f(x) up 4 units.

Hope this helps!

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What is theoretical probability of rolling a number greater than 4 on a standard number cube

sergeinik [125]

So cube faces were numbered 1, 2, 3, 4, 5 and 6.

There are 6 faces in total and there are two faces greater than 4 (face 5 and 6).

So that would be (desired outcomes) / (total outcomes) = 2 / 6 = 1/3

So theoretical probability of rolling a number greater than 4 is 1/3.

Hope this helps.

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3 years ago

Three and two forths - one and two thirds = <br> 3 2/4 - 1 2/3 =

soldier1979 [14.2K]

Answer:

1.83333333333

Step-by-step explanation:

pls mark me brainliest

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3 years ago

A kite on a 100-foot string is fastened to the ground, making a 25° angle with the ground. To the nearest tenth of a foot, how h

lozanna [386]

Answer: 42.3 ft

<u>Step-by-step explanation:</u>

Draw a picture (see attachment)

Given: angle = 25°, hypotenuse = 100, opposite = ???

$\sin\theta=\dfrac{opposite}{hypotenuse}\quad \rightarrow \quad \sin25^o=\dfrac{y}{100}\quad \rightarrow \quad 100\ \sin 25^o=y\\$

$\large\boxed{42.3\ ft}=y$

5 0

3 years ago

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

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3 years ago

If the policy premium on a 30 year $1,000,000 term life policy for a 35-year-old female is increased to $714, what is the percen

Andru [333]

I believe the answer might be B

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3 years ago

Read 2 more answers