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disa [49]
3 years ago
8

What is theoretical probability of rolling a number greater than 4 on a standard number cube

Mathematics
1 answer:
sergeinik [125]3 years ago
8 0
So cube faces were numbered 1, 2, 3, 4, 5 and 6.

There are 6 faces in total and there are two faces greater than 4 (face 5 and 6).

So that would be (desired outcomes) / (total outcomes) = 2 / 6 = 1/3

So theoretical probability of rolling a number greater than 4 is 1/3.

Hope this helps.
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Solve the inequality 2n – 1 < 39​
MatroZZZ [7]

Answer:

n < 20​

Step-by-step explanation:

2n – 1 < 39​

Add 1 to each side

2n – 1+1 < 39+1

2n < 40

Divide each side by 2

2n/2 < 40/2

n < 20​

3 0
2 years ago
If the perimeter of a triangle is 45 cm and the ratio of the 3 sides is 2:3:4, find the length of all 3 sides
frozen [14]

Answer:

Below.

Step-by-step explanation:

2 + 3 + 4 = 9 so

the smallest side = 2/9 * 45, the next = 3/9 * 45 and the longest = 4/9 *45.

= 10, 15 and 20 cm.

5 0
3 years ago
Match the terms below to their definition. Circumcenter
Natasha_Volkova [10]

Answer:

passes through all verrtices of a polygon

Step-by-step explanation:

4 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
(3n^2-5n+6) + (-8n^2-3n-2)=
Aleksandr [31]

Answer:

-5n²-8n+4

Step-by-step explanation:

Remove Parentheses :

3n²-5n+6 - 8n²-3n-2

Collect/Combine Like terms:

(3n²-8n²) + (-5n-3n) +(6-2)

Simplify:

-5n²-8n+4

7 0
3 years ago
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