Ask question

Ask question

All categories

2 years ago

9

Do the attachment for points, and actually write the good answer

1 answer:

deff fn [24]2 years ago

5 0

Answer:

0.75

Step-by-step explanation:

if you divide 100 by 4 you get 25 so 25 is 1/4 so 25 times 3 gets 0.75 out of 100

You might be interested in

Given quadrilateral RSTU, determine if each pair of sides (if any) are parallel and which are perpendicular for the

-BARSIC- [3]

Answer:

US is parallel to RT, and UR is parallel to ST

ST is perpendicular to US and UR is perpendicular to RT

Basically anywhere that there's lines that make right angles are perpendicular to each other

I hope this helps

Step-by-step explanation:

4 0

3 years ago

How to find the measure of angles?

nevsk [136]

Answer:

The best way to measure an angle is to use a protractor. To do this, you'll start by lining up one ray along the 0-degree line on the protractor. Then, line up the vertex with the midpoint of the protractor. Follow the second ray to determine the angle's measurement to the nearest degree.

Step-by-step explanation:

7 0

3 years ago

Your parents gave you a gift card for your favorite coffee shop. The card was worth $50

meriva

Answer:

y=-3x+50

Step-by-step explanation:

y=50-3x ,where x is number of days.

6 0

2 years ago

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

Chen kept track of how many baskets were made in a basketball game. After 6 minutes, 5 baskets were made. How long did it take u

Mekhanik [1.2K]

Answer:

Assuming the same pace was kept, it would take 9.6 minutes.

Step-by-step explanation:

We can find this by setting up a proportion and then cross multiplying.

5 baskets/6 mins = 8 baskets/x mins

5 * x = 6 * 8

5x = 48

x = 9.6

5 0

2 years ago