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maxonik [38]
3 years ago
11

If one term of a proportion is not known, what can be used to find the value of that term? a. substitution c. cross-multiplicati

on b. graphing d. adding all the numbers together
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

cross multiplication

Step-by-step explanation:

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What is the equation, in slope-intercept form, of the line parallel to y = 5x+2 that passes through the point (-2, 1)?
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Y=5x+11 using the point-slope formula and simplifying
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What theorem is this<br>sss,sas,asa,aas,hl, or not enough info​
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ASA - verticals angles are equal, two sides are equal, and two other angles are marked equal
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3 years ago
the initial term of arithmetic sequence is 5. The eleventh term is 125. what is the common difference of the arithmetic sequence
kap26 [50]
An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term
So...
f(x)=mx+b
m=common difference
b=starting point
f(11)=125=11m+b
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f(1)=5=1m+b
--------
120=10m
Divide both sides by 10
12=m
Your common difference is 12.



4 0
3 years ago
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
Anettt [7]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. Favorable cases for Both the laptops to be selected = _2C_2 = 1

Total number of cases = 15

Required probability is \frac{1}{15}.

b. Favorable cases for both the desktop machines selected = _4C_2=6

Total number of cases = 15

Required probability is \frac{6}{15} = \frac{2}{5}.

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

2. Both desktop:

Favorable cases = _4C_2=6

Total number of favorable cases = 8 + 6 = 14

Required probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

Total number of cases = 15

Required probability is \frac{8}{15}.

8 0
3 years ago
Find the y please use the screen shot
Vikki [24]

Answer:

y = 0.3

Step-by-step explanation:

Solve for y:

\longrightarrow (3.2y - 1.8) - (5.2 y + 3.4) = -5.8

-(5.2y + 3.4) = -5.2y - 3.4:

\longrightarrow3.2y - 1.8 -5.2y - 3.4 = -5.8

Grouping like terms, 3.2y - 1.8 - 5.2y - 3.4 = (3.2y - 5.2y) + (-1.8 - 3.4):

\longrightarrow (3.2y - 5.2y) + (-1.8 - 3.4) = -5.8

3.2y - 5.2y = -2 y:

\longrightarrow -2y + (-1.8 - 3.4) = -5.8

-1.8 - 3.4 = -5.2:

\longrightarrow -5.2 - 2y = -5.8

Add 5.2` to both sides:

\longrightarrow (5.2 - 5.2) - 2y = 5.2 - 5.8

5.2 - 5.2 = 0:

\longrightarrow -2y = 5.2 - 5.8

5.2 - 5.8 = -0.6:

\longrightarrow -2y = -0.6

Divide both sides of -2y = -0.6 by -2:

\longrightarrow \sf \dfrac{-2}{-2}y = \dfrac{-0.6}{-2}

\sf \dfrac{-2}{-2} = 1:

\longrightarrow \sf y = \dfrac{-0.6}{-2}

\sf \dfrac{-0.6}{-2} = 0.3:

\longrightarrow y = 0.3

5 0
3 years ago
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