Hj and ik are opposite sides of the rectangle so they areequal in length.
19 + 2x = 3x + 22
19-22 = 3x-2x
x = -3
We can't find the length of the diagonals as we have no information about the width.
Answer:
g(x)![\[ = \left| {4(x + 1)} \right| + 5\]](https://tex.z-dn.net/?f=%5C%5B%20%3D%20%5Cleft%7C%20%7B4%28x%20%2B%201%29%7D%20%5Cright%7C%20%2B%205%5C%5D)
Step-by-step explanation:
Vertically translating a graph is equivalent to shifting the base graph up or down in the direction of the y-axis.
, where K is the shift
Thus,
or ![\[\left| {4x} \right| + 9\]](https://tex.z-dn.net/?f=%5C%5B%5Cleft%7C%20%7B4x%7D%20%5Cright%7C%20%2B%209%5C%5D)
Learn more about transformation of graph:
brainly.com/question/10059147?referrer=searchResults
In this question, both tickets cost 2$ per ticket.
The answer to this question would be: $0
In WinOne scenario, you need to match a ticket that has to pick from A-J(10 possibilities) and 0-9 (10 possibilities). The chance to win would be: 1/10* 1/10= 1/100
The expected value must be:
E= chance to win * win amount - ticket price
E= 1//100*$200 - $2= $2-$2= 0
Answer:
Probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.
Step-by-step explanation:
We are given that a certain car model has a mean gas mileage of 31 miles per gallon (mpg) with a standard deviation 3 mpg.
A pizza delivery company buys 43 of these cars.
<em>Let </em>
<em> = sample average mileage of the fleet </em>
<em />
The z-score probability distribution of sample average is given by;
Z =
~ N(0,1)
where,
= mean gas mileage = 31 miles per gallon (mpg)
= standard deviation = 3 mpg
n = sample of cars = 43
So, probability that the average mileage of the fleet is greater than 30.7 mpg is given by = P(
<em> </em>> 30.7 mpg)
P(
<em> </em>> 30.7 mpg) = P(
>
) = P(Z > -0.66) = P(Z < 0.66)
= 0.7454
<em>Because in z table area of P(Z > -x) is same as area of P(Z < x). Also, the above probability is calculated using z table by looking at value of x = 0.66 in the z table which have an area of 0.7454.
</em>
Therefore, probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.