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alexgriva [62]
3 years ago
8

Oliver has music lessons in Monday Wednesday and Friday.Each lesson is 3/4 of an hour Oliver says he will have lessons for three

and one half hours this week without multiplying explain how you know Oliver is incorrect
Mathematics
1 answer:
Hoochie [10]3 years ago
4 0
Oliver is incorrect because if he were correct he would learn for 2 hours and 15 minutes because, 45 minutes * 3= 2:15 minutes.
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what is 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 12 + 10 + 1 + 8 + 6 + 5 + 8 + 1 + 16 + 84 + 6 + 10 + 10 + 10 + 10
Vanyuwa [196]

Answer:

317

Step-by-step explanation:

8 0
3 years ago
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HIJK is a rectangle. Find the value of x and find the length of each diagonals. If hj=19+2x and ik=3x+22
viva [34]
Hj  and ik are  opposite sides of the rectangle so they areequal in length.

19 + 2x = 3x + 22
19-22 = 3x-2x
x = -3 

We can't find the length of the diagonals as we have no information about the width.
8 0
4 years ago
Write a function g whose graph represents the indicated transformation of the graph of f.
Rudiy27

Answer:

g(x)\[ = \left| {4(x + 1)} \right| + 5\]

Step-by-step explanation:

Vertically translating a graph is equivalent to shifting the base graph up or down in the direction of the y-axis.

\[g\left( x \right) = f\left( x \right) + K\], where K is the shift

Thus, g(x)\[ = \left| {4(x + 1)} \right| + 5\]  or \[\left| {4x} \right| + 9\]

Learn more about transformation of graph:

brainly.com/question/10059147?referrer=searchResults

3 0
3 years ago
A state offers two lottery games, WinOne and PlayBall. Both games cost $2 per ticket.
uysha [10]
In this question, both tickets cost 2$ per ticket.
The answer to this question would be: $0

In WinOne scenario, you need to match a ticket that has to pick from A-J(10 possibilities) and 0-9 (10 possibilities). The chance to win would be: 1/10* 1/10= 1/100

The expected value must be:
E= chance to win * win amount - ticket price
E= 1//100*$200 - $2= $2-$2= 0
8 0
3 years ago
A certain car model has a mean gas mileage of 31 miles per gallon (mpg) with astandard deviation 3 mpg. A pizza delivery company
Effectus [21]

Answer:

Probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.

Step-by-step explanation:

We are given that a certain car model has a mean gas mileage of 31 miles per gallon (mpg) with a standard deviation 3 mpg.

A pizza delivery company buys 43 of these cars.

<em>Let </em>\bar X<em> = sample average mileage of the fleet </em>

<em />

The z-score probability distribution of sample average is given by;

                   Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = mean gas mileage = 31 miles per gallon (mpg)

           \sigma = standard deviation = 3 mpg

           n = sample of cars = 43

So, probability that the average mileage of the fleet is greater than 30.7 mpg is given by = P(\bar X<em> </em>> 30.7 mpg)

     P(\bar X<em> </em>> 30.7 mpg) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{30.7 - 31}{\frac{3}{\sqrt{43} } } ) = P(Z > -0.66) = P(Z < 0.66)

                                                                 = 0.7454

<em>Because in z table area of P(Z > -x) is same as area of P(Z < x). Also, the above probability is calculated using z table by looking at value of x = 0.66 in the z table which have an area of 0.7454. </em>

Therefore, probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.

5 0
3 years ago
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